Question

[phèn văn phở]

làm hộ nhé cảm ơn mn !

Answer 1

[Nguyễn Huy Tú]

Bạn đăng tách ra cho mn cùng giúp nhé 

Bài 3 :

a, \(\frac{x+6}{8}+\frac{x+8}{6}+\frac{x+1}{13}+3=0\)

\(\Leftrightarrow\frac{x+6}{8}+1+\frac{x+8}{6}+1+\frac{x+1}{13}+1=0\)

\(\Leftrightarrow\frac{x+14}{8}+\frac{x+14}{6}+\frac{x+14}{13}=0\)

\(\Leftrightarrow\left(x+14\right)\left(\frac{1}{8}+\frac{1}{6}+\frac{1}{13}\ne0\right)=0\Leftrightarrow x=-14\)

b, \(\frac{x-5}{10}+\frac{x-7}{8}+\frac{x-1}{14}=3\)

\(\Leftrightarrow\frac{x-5}{10}+\frac{x-7}{8}+\frac{x-1}{14}-3=0\)

\(\Leftrightarrow\frac{x-5}{10}-1+\frac{x-7}{8}-1+\frac{x-1}{14}-1=0\)

\(\Leftrightarrow\frac{x-15}{10}+\frac{x-15}{8}+\frac{x-15}{14}=0\)

\(\Leftrightarrow\left(x-15\right)\left(\frac{1}{10}+\frac{1}{8}+\frac{1}{14}\ne0\right)=0\Leftrightarrow x=15\)

Answer 2

[phèn văn phở]

vâng lần sau mik sửa cảm ơn bạn góp ý