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\(a,12\left(x-1\right)=0\\ x-1=0\\ x=1\\ b,45+5\left(x-3\right)=70\\ 5\left(x-3\right)=25\\ x-3=5\\ x=8\\ c,3.x-18:2=12\\ 3.x-9=12\\ 3.x=21\\ x=7\)
bn thu gọn 2 đa thức lại rùi thực hiện phép cộng
546859
a)\(\frac{3x}{7}=\frac{5x-1}{2}=>\frac{6x}{14}=\frac{35x-7}{14}\)
=>6x=35x-7
=>35x-6x=7
=>29x=7
=>\(x=\frac{7}{29}\)
b)\(\frac{2-5x}{3}=\frac{4+x}{5}=>\frac{10-25x}{15}=\frac{12+3x}{15}\)
=>10-25x=12+3x
=>25x+3x=10-12
=>28x=-2
=>\(x=\frac{-2}{28}=-\frac{1}{14}\)
a) ta có p(x)=5x3-3x+7-x
=5x3-(3x+x)+7
= 5x3-4x+7
ta có q(x)=-5x3+2x-3+2x-x2-2
=-5x3+(2x+2x)-(3+2)
=-5x3+4x-5
b) ta có m(x)=5x3-4x+7-5x3+4x-5
=(5x3-5x3)-(4x-4x)+(7-5)
= 0 - 0 +2=2
n(x)=5x3-4x+7+5x3-4x+5
=(5x3+5x3)-(4x+4x)+(7+5)
=10x3-8x+12
c)Để m(x) có nghiệm thì tức là 2=0 =>điều này vô lí, nên m(x)vô nghiệm
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\(A=\frac{5x-2}{x-3}=\frac{5x-15}{x-3}+\frac{-17}{x-3}=\frac{5\left(x-3\right)}{x-3}+\frac{-17}{x-3}=5+\frac{-17}{x-3}\)
để A thuộc Z thì \(5+\frac{-17}{x-3}\in Z\)
=>x-3 thuộc Ư(-17)={1;-1;17;-17}
=>x=4;2;21;-14
5x + x= 150: 2+ 3
6x = 150 : 2 + 3
6x = 75 + 3
6x = 78
x = 78 : 6
x = 13
b,
6x + x = 25 + 3
7x = 28
x = 28 : 7
x = 4
c,
5x + x= 39 - 9
6x = 30
6x = 30 : 6
x = 5
d,
7x - x= 25+ 3 . 4 -1
6x = 25+ 3 . 4 -1
6x = 25 + 12 - 1
6x = 37 - 1
6x = 36
x = 36 : 6
x = 6