Giúp tớ với tớ là ma mới
A= 1/4 +1/5+1/6+1/7 + ...........+1/19
C/m: A> 4/3
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Bài 1:
câu a: 4\(\dfrac{4}{9}\) : 2\(\dfrac{2}{3}\) + 3\(\dfrac{1}{6}\)
= \(\dfrac{40}{9}\) : \(\dfrac{8}{3}\) + \(\dfrac{19}{6}\)
= \(\dfrac{5}{3}\) + \(\dfrac{19}{6}\)
= \(\dfrac{10}{6}\) + \(\dfrac{19}{6}\)
= \(\dfrac{29}{6}\)
b, (15,25 + 3,75) \(\times\) 4 + ( 20,71 + 5,29)\(\times\) 5
= 19 \(\times\) 4 + 26 \(\times\) 5
= 76 + 130
= 206
c, \(\dfrac{4}{5}\) \(\times\) \(\dfrac{1}{2}\) + \(\dfrac{4}{5}\) \(\times\) \(\dfrac{1}{3}\) - \(\dfrac{4}{5}\) \(\times\) \(\dfrac{1}{4}\)
= \(\dfrac{2}{5}\) + \(\dfrac{4}{15}\) - \(\dfrac{1}{5}\)
= \(\dfrac{6}{15}\) + \(\dfrac{4}{15}\) - \(\dfrac{3}{15}\)
= \(\dfrac{7}{15}\)
d, 1\(\dfrac{5}{7}\) + 7\(\dfrac{3}{6}\) + 2\(\dfrac{2}{7}\) - 4\(\dfrac{3}{6}\)
= (1 + 2 + \(\dfrac{5}{7}\) + \(\dfrac{2}{7}\)) + ( 7 + \(\dfrac{3}{6}\) - 4 - \(\dfrac{3}{6}\))
= 3 + 1 + 3
= 7
`3/(-10) ; 1/(-2) ; 4/(-5)=> -3/10 ; -1/2 ; -4/5`
ta có : `-1/2=(-1xx5)/(2xx5)=-5/10 ; -4/5=(-4xx2)/(5xx2)=-8/10`
vậy `3/(-10) < 1/(-2) < 4/(-5)`
`--------------------`
`2/(-10) ; 7/(-5) ; -1/2=>-2/10 ;-7/5;-1/2`
ta có : `-7/5=(-7xx2)/(5xx2)=-14/10; -1/2=(-1xx5)/(2xx5)=-5/10`
vậy `2/(-10) < -1/2 < 7/(-5)`
`---------------------`
`7/(-4) ; -2/5 ; -3/10=> -7/4;-2/5;-3/10`
ta có : `-7/4=(-7xx5)/(4xx5)=-35/20 ; -2/5=(-2xx4)/(5xx4)=-8/20;-3/10=(-3xx2)/(10xx2)=-6/20`
vậy 7/(-4) > -2/5 > -3/10`
a ) 13/20
B)
C..........................................................
minh dang tính
A = ( 1 - 1/2 ) x ( 1 - 1/3 ) x ( 1 - 1/4 ) x ... x ( 1 - 1/19 ) x ( 1 - 1/20 )
A = ( 2/2 - 1/2 ) x ( 3/3 - 1/3 ) x ( 4/4 - 1/4 ) x ... x ( 19/19 - 1/19 ) x ( 20/20 - 1/20 )
A = 1/2 x 2/3 x 3/4 x ... x 18/19 x 19/20
A = 1 x 2 x 3 x ... x 18 x 19/2 x 3 x 4 x ... x 19 x 20
A = 1/20
B = 1/4x5 + 1/5x6 + 1/6x7 + ... + 1/98x99
B = 1/4 - 1/5 + 1/5 - 1/6 + `1/6 - 1/7 + ... + 1/98 - 1/99
B = 1/4 - 1/99
B = 95/396
(1+5/4+3/2+............................+19/4):23
=4/4+5/4+6/4+7/4+8/4+.......................+19/4):23
=\(\frac{4+5+6+........+19}{4}\):23
=\(\frac{184}{4}\):23=46:23=2
\(a,\dfrac{-1}{7}+\dfrac{8}{13}+\dfrac{-6}{7}-1\dfrac{23}{24}-\dfrac{-5}{13}\\ =\dfrac{-1}{7}+\dfrac{8}{13}+\dfrac{-6}{7}-\dfrac{47}{24}+\dfrac{5}{13}\\ =\left(\dfrac{-1}{7}+\dfrac{-6}{7}\right)+\left(\dfrac{8}{13}+\dfrac{5}{13}\right)-\dfrac{47}{24}\\ =-1+1-\dfrac{47}{24}\\ =0-\dfrac{47}{24}\\ =\dfrac{-47}{24}\)
\(b,\left(7\dfrac{4}{9}+4\dfrac{7}{11}\right)-3\dfrac{4}{9}\\ =7\dfrac{4}{9}+4\dfrac{7}{11}-3\dfrac{4}{9}\\ =\left(7\dfrac{4}{9}-3\dfrac{4}{9}\right)+4\dfrac{7}{11}\\ =4+4\dfrac{7}{11}\\ =\dfrac{44}{11}+\dfrac{51}{11}\\ =\dfrac{95}{11}\)