Cho a=28; b=45;d=143
Chứng tỏ rằng ba số a,b,d nguyên tố cùng nhau từng đôi một rồi suy ra BCNN( a;b;d)
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ST
8
31 tháng 7 2018
= 28 + 62 x a x ( a x 1 - a : 1 ) + 28 x 8 + 28
= 28 + 62 x a x ( a - a ) + 28 x 8 + 28
= 28 + 62 xa x 0 + 28 x 8 + 28
= 28 + 0 + 28 x 8 + 28
= 28 x 2 + 28 x 8
= 28 x ( 2 + 8 )
= 28 x 10
= 280
SH
0
2 tháng 3 2018
thay 28 vao pt nhan tu roi am-gm cho cai do luon
Ps: tim Min
HQ
Hà Quang Minh
Giáo viên
16 tháng 9 2023
a)
\(\frac{{28}}{9} \cdot 0,7 + \frac{{28}}{9} \cdot 0,5 = \frac{{28}}{9}.\left( {0,7 + 0,5} \right)\)
b)
\(\begin{array}{l}\frac{{36}}{{13}}:4 + \frac{{36}}{{13}}:9\\ = \frac{{36}}{{13}}.\frac{1}{4} + \frac{{36}}{{13}}.\frac{1}{9}\\ = \frac{{36}}{{13}}.\left( {\frac{1}{4} + \frac{1}{9}} \right)\\ = \frac{{36}}{{13}}.\frac{{13}}{{36}} = 1\end{array}\)
\(\begin{array}{l}\frac{{36}}{{13}}:(4 + 9)\\ = \frac{{36}}{{13}}:13\\ = \frac{{36}}{{13}}.\frac{1}{{13}}\\ = \frac{{36}}{{169}}\end{array}\)
Suy ra \(\frac{{36}}{{13}}:4 + \frac{{36}}{{13}}:9\) \( \ne \) \(\frac{{36}}{{13}}:(4 + 9)\).
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