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\(\text{Because M is the midpoint of line segment AB }\)
\(\Rightarrow AM=BM=60:2=30cm\)
Đào Ngọc Minh Thư
REPLY: a) (A; 3cm) and (B; 2cm) intersect at C; D should: + C, D lie on the circle (A; 3cm), deduce AC = AD = 3cm. + C, D lie on the circle (B; 2cm), deduce BC = BD = 2cm. b) A circle (B; 2cm) cuts section AB at I should: + I lie on the circle (B; 2cm), deduce BI = 2cm. + I is on line AB, deduce IA + IB = AB. Where BI = 2cm; AB = 4cm so AI = 2cm. Hence BI = AI. Combined with I on the line AB deduce I is the midpoint AB. c) The circle (A; 3cm) cuts section AB at K so K belongs to the circle (A; 3cm), deducing AK = 3cm. On the line AB has AI <AK so I is between A and K. Hence AI + IK = AK. Which AK = 3cm; AI = 2cm so IK = 1cm
Exer 1:
Trả lời:
The sum of dividend and divisor are:
195 - 3 = 192
Because the quotient is 6.
The divisor is:
(192-3) : (6+1) = 27
The dividend is:
192 - 27 = 165
Exer 2:
Trả lời:
Let three unknow numbers be: n, n + 1, n + 2.
Because n has three forms: 3k, 3k + 1, 3k + 2.
+) If n
Xin lỗi, mình vẫn chưa viết xong, rồi mình viết tiếp đây:
+) If n = 3k then there is only n divisibles by 3.
+) If n = 3k + 1 then there is only n + 2 divisibles by 3.
+) If n = 3k + 2 then there is only n + 1 divisibles by 3.
Thus, amoney three consecutive natural numbers, there is one only one the number which divisibles by 3.
Exer 3:
Trả lời:
When we written the opposite respectively of n, we obtain \(\overline{1ba1}\).
We have:
\(\overline{1ab1}\) + \(\overline{1ba1}\) = (1000 + 100a + 10b + 1) - (1000 + 100b + 10a + 1)
= 90a - 90b
= 90(a - b)\(⋮\) 90
Thus, the difference of n and m which divisibles by 90.
Given a segment AB = 100cm. Let C be a point between A and B. Let M, N be respectively the midpoint of the segment BC, AC. Find the length of the segment MN.
Answer : MN = 50 cm
P/s : k mình nha bạn