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1. Ư(9) = { -1; -3 ;-9;1;3;9 }
2. 0 12 24 36 48
3 a (28-28) + (-15 + 45) = 0 +30 = 30
b 17 +65 +43 - 43 -65 = 17 + (65-65) + (43-43) =17
c { (-25). (-4) } ( 7.3 ) = 100. 21 =2100
a: \(2\cdot25\cdot4\cdot50\)
\(=\left(2\cdot50\right)\cdot\left(25\cdot4\right)\)
\(=100\cdot100=10000\)
b: \(\left(-125\right)\cdot5\cdot\left(-16\right)\cdot\left(-8\right)\)
\(=-125\cdot5\cdot16\cdot8\)
\(=-\left(125\cdot8\right)\cdot\left(5\cdot16\right)\)
\(=-80\cdot1000=-80000\)
c: \(5^2\cdot3^3\cdot2\)
\(=25\cdot27\cdot2\)
\(=\left(25\cdot2\right)\cdot27=27\cdot50=1350\)
d: \(\left(-4\right)\cdot3^2\left(-5\right)^3\)
\(=\left(-4\right)\cdot\left(-125\right)\cdot9\)
\(=500\cdot9=4500\)
a: \(=\dfrac{-39+19+10}{12}=\dfrac{-10}{12}=\dfrac{-5}{6}\)
b: \(=\dfrac{2^{30}\cdot3^{16}\cdot7-2^{34}\cdot3^{15}}{2^{28}\cdot3^{21}-2^{28}\cdot3^{17}}\)
\(=\dfrac{2^{30}\cdot3^{15}\left(3\cdot7-2^4\right)}{2^{28}\cdot3^{17}\left(3^4-1\right)}=\dfrac{2^2}{3^2}\cdot\dfrac{21-16}{80}=\dfrac{4}{9}\cdot\dfrac{5}{80}\)
\(=\dfrac{20}{720}=\dfrac{1}{36}\)
a) 247 + 629 + 153 + 417 b) 3^5 : 3^2 - 2^2 . 2^0
= ( 247 + 153 ) + ( 629 + 417 ) = 3^5 : 3^2 - 2^2 . 1
= 400 + 1046 = 3^3 - 2^2
= 1446 = 27 - 4
= 23
c) 25 . 43 + 25 . 57 - 150 d) 16 + [ 25 - ( 9^2 - 16.5 )^10 . 24 ]
= 25(43 + 57 ) - 150 = 16 + [ 25 - ( 81 - 80 )^10 . 24 ]
= 25 . 100 - 150 = 16 + [ 25 - 1^10 . 24 ]
= 2500 - 150 = 16 + [ 25 - 1 . 24 ]
= 2350 = 16 + [ 25 - 24 ]
= 16 + 1
= 17
a ) \(247+629+153+417\)
= \(\left(247+153\right)+\left(629+417\right)\)
= \(400+1046\)
= \(1446\)
b) \(3^5:3^2-2^2.2^0\)
= \(3^3-2^2\)
= \(27-4\)
= \(23\)
c) \(25.43+25.57-150\)
= \(25.\left(43+57\right)-150\)
= \(25.100-150\)
= \(2500-150\)
= \(2350\)
d ) \(16+\left[25-\left(9^2-16.5\right)^{10}\right].24\)
= \(16+\left[25-\left(81-80\right)^{10}\right].24\)
= \(16+\left[25-1^{10}\right].24\)
= \(16+\left[25-1.24\right]\)
= \(16+\left[25-24\right]\)
= \(16+1\)
= \(17\)
Chúc bạn học tốt !!!