![](https://rs.olm.vn/images/avt/0.png?1311)
Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
c)
\(30ax-34bx-15a+17b\)
\(=(30ax-15a)-(34bx-17b)\)
\(=15a(2x-1)-17b(2x-1)\)
\(=(2x-1)(15a-17b)\)
d)
\(x^3-x^2y-x^2z-xyz\)
\(=x[x^2-xy-xz-yz]\)
a)
\(12x^3+4x^2-27x-9\)
\(=(12x^3+4x^2)-(27x+9)\)
\(=4x^2(3x+1)-9(3x+1)\)
\(=(3x+1)(4x^2-9)=(3x+1)[(2x)^2-3^2]\)
\(=(3x+1)(2x-3)(2x+3)\)
b)
\(x^6-x^4+2x^3+2x^2\)
\(=x^2(x^4-x^2+2x+2)\)
\(=x^2[x^2(x^2-1)+2(x+1)]\)
\(=x^2[x^2(x-1)(x+1)+2(x+1)]\)
\(=x^2(x+1)[x^2(x-1)+2]\)
\(=x^2(x+1)[(x^3+1)-(x^2-1)]\)
\(=x^2(x+1)[(x+1)(x^2-x+1)-(x-1)(x+1)]\)
\(=x^2(x+1)(x+1)(x^2-x+1-x+1)\)
\(=x^2(x+1)^2(x^2-2x+2)\)
![](https://rs.olm.vn/images/avt/0.png?1311)
Phân tích đa thcusw thành nhân tử (Phương pháp nhân hạng tử):
1. 3a - 3b + ax - bx
= 3(a - b) + x(a - b)
= (a - b)(3 + x)
2. x3 + 3x2 + 3x + 9
= x3 + 3x2 + 3x + 1 + 8
= (x + 1)3 + 8
= (x + 1 + 2)[(x + 1)2 - 2(x + 1) + 4]
= (x + 3)(x2 + 2x + 1 - 2x - 2 + 4)
= (x + 3)(x2 + 3)
3. 10ay - 5by + 2ax - bx
= 5y(2a - b) + x(2a - b)
= (2a - b)(5y + x)
4. 5a2 - 5ax - 7a + 7x
= 5a(a - x) - 7(a - x)
= (a - x)(5a - 7)
5. x2 - 3xy + x - 3x
= x(x - 3y + 1 - 3)
= x(x - 3y - 2)
6. 7x2 - 7xy - 4x + 4y
= 7x(x - y) - 4(x - y)
= (x - y)(7x - 4)
7. 3ax - 4by - 4ay + 3bx
= (3ax + 3bx) - (4ay + 4by)
= 3x(a + b) - 4y(a + b)
= (a + b)(3x - 4y)
8. 30ax - 34bx - 15a + 17b
= (30ax - 15a) - (34bx -17b )
= 15a(x - 1) - 17b(x - 1)
= (x - 1)(15a - 17b)
9. 3x2 - 3xy + 3y2 - 3xy
= 3(x2 - xy + y2 - xy)
= 3(x2 - 2xy + y2)
= 3(x - y)2
10. 12a2 - 6ab + 3b2 - 6ab
= 3(4a2 - 2ab + b2 - 2ab)
= 3(4a2 - 4ab + b2)
= 3(2a - b)2
![](https://rs.olm.vn/images/avt/0.png?1311)
\(=\left(-5a\right)^3+3.\left(-5a\right)^2+3.\left(-5a\right)+1\)
\(=\left(-5a+1\right)^3\)
![](https://rs.olm.vn/images/avt/0.png?1311)
a) x^2 - 2xy + y^2 - xz + yz
= (x^2 - 2xy + y^2 ) - (xz + yz)
= (x - y)^2 - z(x + y)
= (x - y)(x - x + y)
![](https://rs.olm.vn/images/avt/0.png?1311)
a) x2 -2x - 3
= (x2 - 3x) + (x -3)
= x ( x-3) + (x - 3)
= ( x - 3)(x+1)
( Câu này bạn có thể dùng EQN để tính cho nhanh nhé)
b) a4+5a3+15a-9
=(a4-9)+(5a3+15a)
=(a2+3)(a2-3)+5a(a2+3)
=(a2+3)(a2-3+5a)
a) theo đề ta có:
x^2-2x-3=x^2-2x+1-4
=(x-1)^2-2^2
=(x-1-2)(x-1+2)
=(x-3)(x+1)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(4x\left(x-y\right)+3\left(y-x\right)^2=4x\left(x-y\right)+3\left(x-y\right)^2\)
\(=\left(x-y\right)\left[4x+3\left(x-y\right)\right]=\left(x-y\right)\left(7x-3y\right)\)
30ax - 34bx - 15a + 17b
=2x(15a-17b)-1(15a-17b)
=(15a-17b)(2x-1).
\(30ax-34bx-15a+17b.\)
\(=2\times\left(15a-17b\right)-1\times\left(15a-17b\right)\)
\(=\left(15a-17b\right)\times\left(2x-1\right)\)