Question

[bui hang trang]

Tính giá trị biểu thức 

a, \(A=2010^{2010}.\left(7^{10}:7^8-3.16-2^{2010}:2^{2010}\right)\)

b, \(B=\left(\frac{1}{7}+\frac{1}{23}-\frac{1}{1009}\right):\left(\frac{1}{23}+\frac{1}{7}-\frac{1}{1009}+\frac{1}{7}.\frac{1}{23}.\frac{1}{1009}\right)+1:\left(30.1009-160\right)\)

Answer 1

[Đào Trọng Luân]

a,

A = 2010²⁰¹⁰.[7¹⁰:7⁸-3.16-2²⁰¹⁰:2²⁰¹⁰] 

= 2010²⁰¹⁰.[7²-48-1]

= 2010²⁰¹⁰.0 = 0

b,

B = 1

Answer 2

[park_shin_hye]

\(A=2010^{2010}.\left[7^{10}:7^8-3.16-2^{2010}:2^{2010}\right]\)

\(A=2010^{2010}.\left[7^2-48-1\right]\)

\(A=2010^{2010}.0\)

\(Vay\)\(A=0\)