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Ta có : \(\frac{3}{2x+1}+\frac{10}{4x+2}-\frac{6}{6x+3}=\frac{12}{26}\)
\(\Rightarrow\frac{3}{2x+1}+\frac{5.2}{2\left(2x+1\right)}-\frac{3.2}{3\left(2x+1\right)}=\frac{6}{13}\)
=> \(\frac{3}{2x+1}+\frac{5}{2x+1}-\frac{2}{2x+1}=\frac{6}{13}\)
=> \(\frac{3+5-2}{2x+1}=\frac{6}{13}\)
=> \(\frac{6}{2x+1}=\frac{6}{13}\)
=> 2x + 1 = 13
=> 2x = 12
=> x = 6
Vậy x = 6
\(\frac{3}{2x+1}+\frac{10}{2\left(2x+1\right)}-\frac{6}{3\left(2x+1\right)}=\frac{6}{13}\)
\(\frac{3}{2x+1}+\frac{5}{2x+1}-\frac{2}{2x+1}=\frac{6}{13}\)
\(\frac{6}{2x+1}=\frac{6}{13}\)
\(\Rightarrow2x+1=13\left(6=6\right)\)
\(2x=12\)
\(x=6\)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\frac{3}{2x+1}+\frac{10}{4x+2}-\frac{6}{6x+3}=\frac{12}{26}\)
\(\frac{3}{2x+1}+\frac{2.5}{2\left(2x+1\right)}-\frac{2.3}{3\left(2x+1\right)}=\frac{6}{13}\)
\(\frac{3}{2x+1}+\frac{5}{2x+1}-\frac{2}{2x+1}=\frac{6}{13}\)
\(\frac{3+5-2}{2x+1}=\frac{6}{13}\)
\(\frac{6}{2x+1}=\frac{6}{13}\)
\(2x+1=13\)
\(\Rightarrow x=6\)
\(\frac{3}{2x+1}+\frac{10}{4x+2}-\frac{6}{6x+3}=\frac{12}{26}\)
\(\frac{3}{2x+1}+\frac{2.5}{2\left(2x+1\right)}-\frac{3.2}{3\left(2x+1\right)}=\frac{6}{13}\)
\(\frac{3}{2x+1}+\frac{5}{2x+1}-\frac{2}{2x+1}=\frac{6}{13}\)
\(\frac{6}{2x+1}=\frac{6}{13}\)
\(\Rightarrow2x+1=13\)
\(\Rightarrow2x=12\)
\(\Rightarrow x=6\)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\frac{3}{2x+1}\)+ \(\frac{10}{4x+2}\) - \(\frac{6}{6x+3}\) = \(\frac{12}{26}\)
\(\dfrac{3}{2x+1}\) + \(\dfrac{2.5}{2\left(2x+1\right)}\) - \(\dfrac{2.3}{3\left(2x+1\right)}\) = \(\dfrac{6}{13}\)
\(\dfrac{3}{2x+1}\) + \(\dfrac{5}{2x+1}\) - \(\dfrac{2}{2x+1}\) = \(\dfrac{6}{13}\)
\(\dfrac{3}{2x+1}\) + \(\dfrac{5}{2x+1}\) + \(\dfrac{-2}{2x+1}\) = \(\dfrac{6}{13}\)
\(\dfrac{6}{2x+1}\) = \(\dfrac{6}{13}\)
\(\Rightarrow\) (2x+1).6 = 6.13 2x + 1 = \(\dfrac{6.13}{6}\) 2x + 1 = 13 2x = 13 - 1 2x = 12 x = 12:2 x = 6 Vậy x = 6
Ta có: \(\dfrac{3}{2x+1}+\dfrac{10}{4x+2}-\dfrac{6}{6x+3}\)= \(\dfrac{3}{2x+1}+\dfrac{5}{2x+1}-\dfrac{2}{2x+1}\)
= \(\dfrac{3+5-2}{2x+1}=\dfrac{6}{2x+1}=\dfrac{12}{26}\) \(\Rightarrow156=24x+12\Rightarrow24x=144\Rightarrow x=6\)
Vậy x=6.
Học tốt nha
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\frac{3}{2x+1}+\frac{10}{4x+2}-\frac{6}{6x+3}=\frac{6}{13}\)
\(\Rightarrow\frac{3}{2x+1}+\frac{5}{2x+1}-\frac{2}{2x+1}=\frac{6}{13}\)
\(\Rightarrow\frac{6}{2x+1}=\frac{6}{13}\Rightarrow2x+1=13\Rightarrow x=6\)
mình giải hơi gọn có gì ko hiểu thì hỏi nha !
![](https://rs.olm.vn/images/avt/0.png?1311)
a, \(\frac{x-4}{12}=\frac{x-6}{11}\)
\(\Rightarrow11\left(x-4\right)=12\left(x-6\right)\)
\(\Rightarrow11x-44=12x-72\)
\(\Rightarrow11x-12x=-72+44\)
\(\Rightarrow-x=-28\)
=> x = 28
b, \(\frac{3x+2}{-7}=\frac{x-4}{-2}\)
\(\Rightarrow-2\left(3x+2\right)=-7\left(x-4\right)\)
\(\Rightarrow-6x+\left(-4\right)=-7x-\left(-28\right)\)
\(\Rightarrow-6x+\left(-4\right)=-7x+28\)
\(\Rightarrow-6x+7x=28-\left(-4\right)\)
\(\Rightarrow x=32\)
c, \(\frac{1-4x}{5}=\frac{2x-1}{-3}\)
\(\Rightarrow-3\left(1-4x\right)=5\left(2x-1\right)\)
\(\Rightarrow-3-\left(-12x\right)=10x-5\)
\(\Rightarrow-3+12x=10x-5\)
\(\Rightarrow-3+5=10x-12x\)
\(\Rightarrow2=-2x\)
=> x = 2 : (-2)
=> x = -1