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a) \(-\frac{1}{4}.13\frac{9}{11}-0,25.6\frac{2}{11}\)
\(=-\frac{1}{4}.13\frac{9}{11}-\frac{1}{4}.6\frac{2}{11}\)
\(=-\frac{1}{4}\left(13\frac{9}{11}+6\frac{2}{11}\right)\)
\(=-\frac{1}{4}.20\)
\(=-5\)
b) \(B=\frac{-5}{6}.\frac{4}{19}+\frac{-7}{12}.\frac{4}{19}-\frac{40}{57}\)
\(=\frac{4}{19}\left(\frac{-5}{6}+\frac{-7}{12}\right)-\frac{40}{57}\)
\(=\frac{4}{19}.\frac{-17}{12}-\frac{40}{57}\)
\(=\frac{-17}{57}-\frac{40}{57}\)
\(=-1\)
c) \(\frac{3}{7}.\frac{9}{26}-\frac{1}{14}.\frac{1}{13}-\frac{1}{7}\)
\(=\frac{3}{7}.\frac{9}{26}-\frac{1}{2}.\frac{1}{7}.\frac{1}{13}-\frac{1}{7}\)
\(=\frac{1}{7}\left(3.\frac{9}{26}-\frac{1}{2}.\frac{1}{13}-1\right)\)
\(=\frac{1}{7}.0\)
\(=0\)
d) \(\frac{4}{9}:\left(-\frac{1}{7}\right)+6\frac{5}{9}:\left(-\frac{1}{7}\right)\)
\(=\left(\frac{4}{9}+6\frac{5}{9}\right):\left(-\frac{1}{7}\right)\)
\(=7:\left(-\frac{1}{7}\right)\)
\(=-49\)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\frac{3}{7}\times\frac{9}{26}-\frac{1}{14}\times\frac{1}{13}\)
\(=\frac{27}{182}-\frac{1}{182}\)
\(=\frac{1}{7}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\left(1+2\frac{1}{4}-3\frac{1}{3}\right):\left(1+3\frac{1}{2}-4\frac{7}{12}\right)\)
\(=\left(1+2-3+\frac{1}{4}-\frac{1}{3}\right):\left(1+3-4+\frac{1}{2}-\frac{7}{12}\right)\)
\(=\frac{-1}{12}:\frac{-1}{12}=\frac{-1}{12}.\frac{12}{-1}=\frac{12}{12}=1\)
a. (1 + \(2\frac{1}{4}\) - \(3\frac{1}{3}\)) : (1 + \(3\frac{1}{2}\) - \(4\frac{7}{12}\))
= \(-\frac{1}{12}\): ( \(-\frac{1}{12}\))
= 1
b. \(5\frac{1}{2}\)- \(14\frac{3}{7}\) : \(\frac{9}{13}\)- \(3\frac{4}{7}\) : \(\frac{9}{13}\)
= \(\frac{11}{2}\)+ (\(14\frac{3}{7}-3\frac{4}{7}\)) : \(\frac{9}{13}\)
= \(\frac{11}{2}\)- 26
= \(-\frac{41}{2}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
= \(\frac{11}{2}\)- \(\frac{101}{7}\): \(\frac{9}{13}\)- \(\frac{25}{7}\): \(\frac{9}{13}\)
= \(\frac{-41}{2}\)
(chỉ cần sử dụng máy tính cầm tay là có thể giải được)
hãy tìm ba phân số lớn hơn \(\frac{1}{3}\)và nhỏ hơn\(\frac{1}{2}\)sau đó hãy tính tổng ba phân số vừa tìm được ở trên.
![](https://rs.olm.vn/images/avt/0.png?1311)
C = \(\frac{3}{7}\cdot\frac{9}{26}-\frac{1}{14}\cdot\frac{1}{13}-\frac{1}{7}\)
C = \(\frac{1}{7}\cdot3\cdot\frac{9}{26}-\frac{1}{7}\cdot\frac{1}{2}\cdot\frac{1}{13}-\frac{1}{7}\)
C = \(\frac{1}{7}\cdot\frac{27}{26}-\frac{1}{7}\cdot\frac{1}{26}-\frac{1}{7}\)
C = \(\frac{1}{7}\left(\frac{27}{26}-\frac{1}{26}-1\right)\)
C = \(\frac{1}{7}\left(1-1\right)\)
C = 0
Chúc bn học tốt
![](https://rs.olm.vn/images/avt/0.png?1311)
B= \(5\frac{1}{2}\)- \(\left(14\frac{3}{7}-3\frac{4}{7}\right):\frac{9}{13}\)
= \(5\frac{1}{2}-10\frac{6}{7}:\frac{9}{13}\)
=\(5\frac{1}{2}-\frac{76}{7}\)x\(\frac{13}{9}\)
=\(5\frac{1}{2}\)\(-\)\(13\frac{31}{36}\)
=\(5\frac{13}{36}\)\(-13\frac{31}{36}\)
= \(\frac{193}{36}\)\(-\)\(\frac{499}{36}\)
=\(\frac{153}{13}\)
Nhớ k nha
C1:3/7 x 9/26 - 1/14 x 1/13 - 1/7
=27/182 - 1/182 -1/7
=26/182 - 1/7
=0
bằng 0 nha