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![](https://rs.olm.vn/images/avt/0.png?1311)
A = x + ( 2856 - x )
A = x + 2856 - x
A = ( x - x ) + 2856
A = 0 + 2856
A = 2856
B = x - ( x - 6820 )
B = x - x + 6820
B = 0 + 6820
B = 6820
a/
Ta có: A=x+(2856-x)
=x+2856-x=x-x+2856
=0+2856
=2856
b/
B=x-(x-6820)
=x-x+6820=0+6820
=6820
![](https://rs.olm.vn/images/avt/0.png?1311)
Bài làm
x + ( 2856 - x ) = x + 2856 - x
= 2856
x - ( x - 6820 ) = x - x + 6820
= 6820
![](https://rs.olm.vn/images/avt/0.png?1311)
\(A.x+\left(2856-x\right)=x+2856-x=2856\)
\(B.x-\left(x-6820\right)=x-x+6820=6820\)
![](https://rs.olm.vn/images/avt/0.png?1311)
a)
x+(2856-x)
=x + 2856 -x
=x-x+2856
=0+2856
=2856
b)
x-(x-6820)
=x-x+6820
=0+6820
=6820
![](https://rs.olm.vn/images/avt/0.png?1311)
a. X+(2856-X)=X+2856-X=2856
b.X-(X-6820)=X-X+6820=6820
k cho mình nhé
![](https://rs.olm.vn/images/avt/0.png?1311)
a ) x + ( 2856 - x ) b ) x - ( x - 6820 )
= x + 2856 - x = x - x + 6820
= x - x + 2856 = 0 + 6820
= 0 + 2856 = 6820
= 2856
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\left(1-\dfrac{1}{3}\right)\times\left(1-\dfrac{1}{4}\right)\times\left(1-\dfrac{1}{5}\right)\times\left(1-\dfrac{1}{6}\right)\times\dots\times\left(1-\dfrac{1}{99}\right)\times\left(1-\dfrac{1}{100}\right)\) (sửa đề)
\(=\dfrac{2}{3}\times\dfrac{3}{4}\times\dfrac{4}{5}\times\dfrac{5}{6}\times\dots\times\dfrac{98}{99}\times\dfrac{99}{100}\)
\(=\dfrac{2\times3\times4\times5\times\dots\times98\times99}{3\times4\times5\times6\times\dots\times99\times100}\)
\(=\dfrac{2}{100}\)
\(=\dfrac{1}{50}\)
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