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\(B=\dfrac{\left(2^3.5^4.11\right).\left(2.5^2.11^2\right)}{\left(2^2.5^3.11\right)^2}\)
\(\Leftrightarrow B=\dfrac{2^3.5^4.11.2.5^2.11^2}{2^4.5^9.11^2}\)
\(\Leftrightarrow B=\dfrac{2^4.5^6.11^3}{2^4.5^9.11^2}\)
\(\Leftrightarrow B=\dfrac{11}{5^3}\)
\(\Leftrightarrow B=\dfrac{11}{125}\)
Vậy...
\(B=\dfrac{2^4\cdot5^6\cdot11^3}{2^4\cdot5^6\cdot11^2}=11\)
\(C=\frac{\left(2^3.5^4.11\right).\left(2.5^3.11^2\right)}{\left(2^2.5^3.11\right)^2}\)
\(C=\frac{2^4.5^7.11^3}{2^4.5^6.11^2}\)
\(C=5.11\)
\(C=55\)
Chúc bn học tốt !!!!
\(a.\frac{2\cdot\left(-13\right)\cdot9\cdot10}{\left(-3\right)\cdot4\cdot\left(-5\right)\cdot26}\)
\(=\frac{2\cdot\left(-13\right)\cdot3\cdot3\cdot2\cdot5}{\left(-3\right)\cdot2\cdot2\cdot\left(-5\right)\cdot13\cdot2}\)
\(=-\frac{3}{2}\)
b) \(\frac{2^3\cdot3^4}{2^2\cdot3^2\cdot5}=\frac{2\cdot3^2}{5}=\frac{2\cdot9}{5}=\frac{18}{5}\)
\(\frac{2^4\cdot5^2\cdot11^2\cdot7}{2^3\cdot5^3\cdot7^2\cdot11}=\frac{2\cdot1\cdot11\cdot1}{1\cdot5\cdot7\cdot1}=\frac{22}{35}\)
c) \(\frac{121\cdot75\cdot130\cdot169}{39\cdot60\cdot11\cdot198}=\frac{11\cdot11\cdot13\cdot10\cdot169}{13\cdot3\cdot6\cdot10\cdot11\cdot11\cdot6\cdot3}\)
\(=\frac{169}{3\cdot6\cdot6\cdot3}=\frac{169}{324}\)
d) \(\frac{1998\cdot1990+3978}{1992\cdot1991-3984}\)
\(\frac{1}{2.5}+\frac{1}{5.8}+...+\frac{1}{\left(3n-1\right)\left(3n+2\right)}\)
\(=\frac{1}{3}.\left(\frac{3}{2.5}+\frac{3}{5.8}+...+\frac{3}{\left(3n-1\right)\left(3n+2\right)}\right)\)
\(=\frac{1}{3}.\left(\frac{1}{2}-\frac{1}{5}+\frac{1}{5}-\frac{1}{8}+...+\frac{1}{3n-1}-\frac{1}{3n+2}\right)\)
\(=\frac{1}{3}.\left(\frac{1}{2}-\frac{1}{3n+2}\right)\)
\(=\frac{1}{3}.\frac{3n}{2.\left(3n+2\right)}\)
\(=\frac{n}{2\left(3n+2\right)}\)
Ta có :
\(B=\frac{3^2.5^2.7^2.3^3.7^2}{3^2.5^2.7^4}=\frac{3^4.5^2.7^4}{3^2.5^2.7^4}=\frac{3^4}{3^2}=3^2=9\)
Vậy B = 9.
k nha bạn
B=\(\frac{\left(9.25.49\right).\left(9.49\right)}{735^2}\)
B=\(\frac{11025.441}{540225}\)
B=\(\frac{4862025}{540225}\)
B=9
\(\frac{2^4.5^7.11^3}{2^4.5^611^2}=5.11=55\)
mk trả lời dùm nek