Question

[Phạm Nguyễn Minh Quân]

[1-1/4] nhân [1-1/9] nhân [1-1/16] nhân ...... nhân[1-1/100]

Ai làm được thì gửi nhanh nhé vì mai nộp rồi

Answer 1

[Xyz OLM]

\(\left(1-\frac{1}{4}\right)\left(1-\frac{1}{9}\right)\left(1-\frac{1}{16}\right)....\left(1-\frac{1}{100}\right)=\frac{3}{4}.\frac{8}{9}.\frac{15}{16}...\frac{99}{100}=\frac{3.8.15...99}{4.9.16...100}\)

\(=\frac{1.3.2.4.3.5...9.11}{2.2.3.3.4.4...10.10}=\frac{\left(1.2.3...9\right)\left(3.4.5...11\right)}{\left(2.3.4...10\right)\left(2.3.4...10\right)}=\frac{1.11}{10.2}=\frac{11}{20}\)

Answer 2

[Nguyễn Minh Đăng]

Bài làm:

Ta có: \(\left(1-\frac{1}{4}\right)\left(1-\frac{1}{9}\right)\left(1-\frac{1}{16}\right)...\left(1-\frac{1}{100}\right)\)

\(=\frac{3}{4}.\frac{8}{9}.\frac{15}{16}...\frac{99}{100}\)

\(=\frac{1.3}{2^2}.\frac{2.4}{3^2}.\frac{3.5}{4^2}...\frac{9.11}{10^2}\)

\(=\frac{\left(1.2.3...9\right)\left(3.4.5...11\right)}{\left(2.3.4...10\right)\left(2.3.4...10\right)}=\frac{11}{10.2}=\frac{11}{20}\)

Học tốt!!!!