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a, -154+(x-9-18)=40
x-27=40-(-154)
x-27=194
x=194+27
x=221
b,\(\left|9-x\right|\)=64+(-7)
\(\left|9-x\right|\)=57
TH1:
9-x=57
x=9-57
x=-48
TH2:
9-x=-57
x=9-(-57)
x=66
a, -154+(x-9-18)=40
x-27=40-(-154)
x-27=194
x=194+27
x=221
b,|9−x||9−x|=64+(-7)
|9−x||9−x|=57
TH1:
9-x=57
x=9-57
x=-48
TH2:
9-x=-57
x=9-(-57)
x=66
\(a,\frac{7}{15}\cdot\frac{4}{5}+\frac{7}{15}\cdot\frac{1}{5}-\frac{7}{15}\)
\(=\frac{7}{15}\left(\frac{4}{5}+\frac{1}{5}-1\right)\)
\(=\frac{7}{15}\cdot0\)
\(=0\)
\(b,\frac{9}{25}\cdot\frac{7}{18}+\frac{9}{26}\cdot\frac{1}{3}+\frac{9}{25}\cdot\frac{1}{9}\)
\(=\frac{9}{25}\left(\frac{7}{18}+\frac{1}{3}+\frac{1}{9}\right)\)
\(=\frac{9}{25}\cdot\frac{5}{6}\)
\(=\frac{3}{10}\)
a)4.(x-3)=7.2-1.10
4.(x-3)=14-10
4.(x-3)=4
x-3=4:4
x-3=1
x=1+3
x=4
b)2.(x-51)=2.2.3+20
2.(x-51)=32
x-51=32:2
x-51=16
x=16+51
x=67
c)9.x-1=9
9.x=9+1
9.x=10
x=10:9
x=1,1111111...
(x-2).4=16
x-2=16:4
x-2=4
x=4+2
x=6
Vì x:y=7:(-9)
\(\Rightarrow\frac{x}{8}=\frac{y}{-9}\)
Áp dụng t/c dãy tỉ số bằng nhau ta có:
\(\Rightarrow\frac{x}{8}=\frac{y}{-9}=\frac{x+y}{8+-9}=\frac{18}{-1}=-18\)
\(\Rightarrow\hept{\begin{cases}\frac{x}{8}=-18\\\frac{y}{-9}=-18\end{cases}\Rightarrow\hept{\begin{cases}x=-144\\y=162\end{cases}}}\)
\(x:y=\frac{7}{-9}=>\frac{x}{y}=\frac{7}{-9}=>\frac{x}{7}=\frac{y}{-9}\)
Theo t/c dãy tỉ số=nhau:
\(\frac{x}{7}=\frac{y}{-9}=\frac{x+y}{7-9}=\frac{18}{-2}=-9\)
\(\left(+\right)\frac{x}{7}=-9=>x=-63\)
\(\left(+\right)\frac{y}{-9}=-9=>y=81\)
câu 1; \(-154+\left(x-9-18\right)=40\)
\(\Leftrightarrow-154+x-9-18=40\)
\(\Leftrightarrow x=40+154+9+18\)
\(\Leftrightarrow x=221\)
Câu 2: \(\left|9-x\right|=64+\left(-7\right)\)
\(\Leftrightarrow\left|9-x\right|=57\)
\(\Leftrightarrow\orbr{\begin{cases}9-x=57\\9-x=-57\end{cases}\Rightarrow\orbr{\begin{cases}x=9-57\\x=-57-9\end{cases}\Rightarrow}\orbr{\begin{cases}x=-48\\x=-66\end{cases}}}\)
Vậy...
hok tốt!!
-154+x-9-18=40 x=40+54+9=18 x=221 Vậy x=221