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\(\frac{6^2.15-6^3}{13.3^2-4.3^2}\)
\(=\frac{6^2.15-6^2.6}{\left(13-4\right)3^2}\)
\(=\frac{6^2\left(15-6\right)}{9.3^2}\)
\(=\frac{6^2.9}{9.3^2}\)
\(=\frac{6^2}{3^2}\)
\(=\frac{3^2.2^2}{3^2}\)
\(=2^2\)
\(=4\)
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\(\frac{6^2.15-6^3}{13.3^2-4.3^2}=\frac{6^2\left(15-1\right)}{3^2\left(13-4\right)}=\frac{6^2.14}{3^2.9}=\frac{2^3.3^2.7}{3^4}=\frac{2^3.7}{3^2}=\frac{56}{9}\)
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\(=13\cdot\dfrac{3^n}{3^m\cdot2^m}=\dfrac{13\cdot3^{n-m}}{2^m}\)
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Câu 1 xem kỉ đề
\(B,\frac{49^6.5-7^{11}}{\left(-7\right)^{10}.5-2.49^5}=\frac{7^{12}.5-7^{11}}{7^{10}.5-2.7^{10}}=\frac{7^{11}.\left(7.5-1\right)}{7^{10}.\left(5-2\right)}=\frac{7.34}{3}=\frac{238}{3}\)
a) A=212.35-\(\frac{2^{12}.3^6}{2^{12}}\)+93+84.35
=212.35-36+36+212.35
=213.35
b)B=496.5-5.\(\frac{7^{11}}{\left(-7\right)^{10}}-2.49^5\)
=496.5-7.5-2.495
=712.5-7.5-2.710
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Ta có :
\(\frac{4.5}{2.15}=\frac{2.1}{1.3}=\frac{2}{3}\)
Tham khảo nha !!!
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=324/133