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Question

PTĐTTNT:a) mx2 - 4mx + 4m - nx2 + 4nx - 4nb) 3x2 + 48 + 24x - 12y2

Lê Tài Bảo Châu · Accepted Answer

a) $mx^2-4mx+4m-nx^2+4nx-4n$$=\left(mx^2-nx^2\right)-\left(4mx-4nx\right)+\left(4m-4n\right)$$=x^2\left(m-n\right)-4x\left(m-n\right)+4\left(m-n\right)$$=\left(m-n\right)\left(x^2-4x+4\right)$$=\left(m-n\right)\left(x-2\right)^2$b) $3x^2+48+24x-12y^2$$=3\left(x^2+8x+16-4y^2\right)$$=3\left[\left(x+4\right)^2-\left(2y\right)^2\right]$$=3\left(x+4-2y\right)\left(x+4+2y\right)$Câu trả lời: a) $mx^2-4mx+4m-nx^2+4nx-4n$$=\left(mx^2-nx^2\right)-\left(4mx-4nx\right)+\left(4m-4n\right)$$=x^2\left(m-n\right)-4x\left(m-n\right)+4\left(m-n\right)$$=\left(m-n\right)\left(x^2-4x+4\right)$$=\left(m-n\right)\left(x-2\right)^2$b) $3x^2+48+24x-12y^2$$=3\left(x^2+8x+16-4y^2\right)$$=3\left[\left(x+4\right)^2-\left(2y\right)^2\right]$$=3\left(x+4-2y\right)\left(x+4+2y\right)$

Hoàng Ninh · Answer

a) $mx^2-4mx+4m-nx^2+4nx-4n$$=\left(mx^2-nx^2\right)-\left(4mx+4nx\right)+\left(4m-4n\right)$$=x^2\left(m-n\right)-4x\left(m-n\right)+4\left(m-n\right)$$=\left(m-n\right).\left(x^2-4x+4\right)$$=\left(m-n\right).\left(x-2\right)^2$b) $3x^2+48+24x-12y^2$$=3\left(x^2+16+8x-4y^2\right)$$=3\left[\left(x^2+8x+16\right)-\left(2y\right)^2\right]$$=3\left[\left(x+4\right)^2-\left(2y\right)^2\right]$$=3\left(x+4-2y\right).\left(x+4+2y\right)$Câu trả lời: a) $mx^2-4mx+4m-nx^2+4nx-4n$$=\left(mx^2-nx^2\right)-\left(4mx+4nx\right)+\left(4m-4n\right)$$=x^2\left(m-n\right)-4x\left(m-n\right)+4\left(m-n\right)$$=\left(m-n\right).\left(x^2-4x+4\right)$$=\left(m-n\right).\left(x-2\right)^2$b) $3x^2+48+24x-12y^2$$=3\left(x^2+16+8x-4y^2\right)$$=3\left[\left(x^2+8x+16\right)-\left(2y\right)^2\right]$$=3\left[\left(x+4\right)^2-\left(2y\right)^2\right]$$=3\left(x+4-2y\right).\left(x+4+2y\right)$

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