Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
a) A = (7-9)3+ (-5)7 :(-5)5 +20100=(-2)3 + (-5)7-5 +1
=-8 +(-5)2 +1 = -8 +25 +1=18
B) b=(2.(-2)2 +1:(-3)2) +9.7 -(-2)6 =2.4 +1/9 + 63 - 64 = 8 +1/9 -1 =64/9
CHÚC BN GIỎI NHÉ <3
a,\(2^4\cdot3^5:6^4\)
\(=\frac{2^4\cdot3^6}{\left(2\cdot3\right)^4}\)
\(=\frac{2^4\cdot3^6}{2^4\cdot3^4}\)
\(=3^2\)
Bài 2
\(a,5^3\cdot8=5^3\cdot2^3=10^3=1000\)
\(b,2^5-2019^0=32-1=31\)
\(c,3^3+2^5-1^{10}=27+32-1=58\).
\(d,9^2\cdot33-81\cdot23+5^2=81\cdot33-81\cdot23+25\)
\(=81\cdot\left(33-23\right)+25\)
\(=810+25=835\)
\(g,\left[2^2+6^2\right]:5+11^2\)
\(=\left[4+36\right]:5+121\)
\(=40:5+121=8+121\)
\(=129\)
\(d,\frac{14\cdot3^{10}-5\cdot3^{10}}{3^{12}}\)
\(=\frac{3^{10}\cdot\left(14-5\right)}{3^{12}}\)
\(=\frac{3^{10}\cdot9}{3^{12}}\)
\(=\frac{3^{10}\cdot3^2}{3^{12}}=\frac{3^{12}}{3^{12}}\)
\(=1\)
5.5.3.15.25.9 = 5.5.3.3.5.5.5.3.3 = 5^5.3^4
9.21.7.9.49 = 3.3.3.7.7.3.3.7.7 = 3^5.7^4
10.2.5.4.25.10 = 2.5.2.5.2.2.5.5.2.5 = 2^5.5^5
8.4.10.25 = 2.2.2.2.2.2.5.5.5 = 2^6.5^3
515:53 = 515-3 = 512
15.5.9.15.625.81
= 3.5.5.3.3.3.5.5.5.5.5.3.3.3.3 = 3^8.5^6
18.42.7.9.49 = 2.3.3.2.3.7.7.3.3.7.7 =2^2.3^5.7^4
121.2.125.4.25.11
= 11.11.2.5.5.5.2.2.5.5.11 = 11^3.2^3.5^5
36.4.15.75 = 2.3.2.3.2.2.3.5.5.5.3
= 2^4.3^4.5^3
3^7.5^18.15^6 = 3^7.5^18. 3^6.5^6 = 3^13.5^24
Viết lại đề:
a)\(5.5.4.15.25.9\)
b)\(9.21.7.3.49\)
c)\(3^7.5^{18}:15^6\)
d)\(2.4.8.16.32.64...3^9\)
e)\(3.27.243...3^9\)
Bài 2:
a)\(5^x+3< 5^6\)
b)\(\left(3^2\right)^2+2^{x=5}.\left(5+2^2.3\right)\)
Mik chỉ ghi lại đề cho mn dễ giải thui chứ tui lười giải :D
d: Ta có: \(D=5^3+6^3+59\)
\(=125+216+59\)
\(=400=20^2\)
\(B=5.3^2+4.3^2=3^2\left(5+4\right)=9.9=9^2\)
\(C=5^3+6^3+59=125+216+59=400=20^2\)
\(D=5.4^3+2^4.5+41=320+80+41=441=21^2\)
b: \(5\cdot3^2+4\cdot3^2=3^2\cdot9=3^4\)
c: \(5^3+6^3+59=20^2\)
\(5\cdot4^3+2^4\cdot5+41=21^2\)
Là sao
{x^2−[6^2−(8^2−9⋅7)^3−7⋅5]^3−5⋅3}^3=1
⇒x^2−[36−(64−63)^3−35]^3−15=1
⇒x^2−[36−35−1^3]^3=16
⇒x^2−0^3=16
⇒x^2=16
⇒x=±4
Hok tốt