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0,5x - 2/3x = 5/12
=> x(0,5 - 2/3) = 5/12
=> -1/6x = 5/12
=> x = (5/12) / (-1/6)
=> x = -5/2
![](https://rs.olm.vn/images/avt/0.png?1311)
a)
5.(12-x)-20=30
⇒60-5x-20=30
⇒-5x=30+20-60
⇒-5x=-10
⇒x=2
b)(17x - 25 ) : 8 + 65 = 92
(17x - 25 ) : 8 + 65 = 81
17x - 25 = 16 x 8 = 128
17x = 128+25=153
x= 153:17 =9
c)
x=23
Giải thích các bước giải:
3x – 10 = 2x + 13
3x-2x=13+10
x=23
d)4(2x+7)-3(3x-2)=24
4.2x+4.7-3.3x+3.2=24
8x+28-9x+6=24
8x-9x=24-28-6=-10
=>(-1)x=-10
x=-10:(-1)
x=10
a. \(5\cdot\left(12-x\right)-20=30\Leftrightarrow5\left(12-x\right)=50\)
\(\Leftrightarrow12-x=50:5=10\)
\(\Leftrightarrow x=12-10=2\)
b. \(\left(17x-25\right):8+65=9^2\)
\(\Leftrightarrow\left(17x-25\right):8=81-65=16\)
\(\Leftrightarrow17x-25=16:8=2\)
\(\Leftrightarrow17x=2+25=27\Leftrightarrow x=\frac{27}{17}\)
c. \(3x-10=2x+13\)
\(\Leftrightarrow3x-2x=10+13\)
\(\Leftrightarrow x=23\)
d. \(4\cdot\left(2x+7\right)-3\cdot\left(3x-2\right)=24\)
\(\Leftrightarrow8x+28-9x+6=24\)
\(\Leftrightarrow34-x=24\Leftrightarrow x=10\)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(15-2\left(3x+1\right)=9^2\cdot4^2\cdot5\)
\(=15-2\left(3x+1\right)=6480\)
\(\Rightarrow2\left(3x+1\right)=15-6480=-6465\)
\(\Rightarrow3x+1=-6465:2=-3232,5\)
\(\Rightarrow3x=-3232,5-1=-3233,5\)
\(\Rightarrow x=-3233,5:3=\frac{-6467}{6}=-1077,833333\)
![](https://rs.olm.vn/images/avt/0.png?1311)
`(3x-3^4)*9^3=9^5`
`(3x-3^4)=9^5:9^3`
`(3x-3^4)=9^2`
`3x=9^2+3^4`
`3x=162`
`x=162:3`
`x=54`
`***2k10`
![](https://rs.olm.vn/images/avt/0.png?1311)
\(0,5x-\frac{2}{3}x=\frac{5}{12}\)
\(\frac{1}{2}x-\frac{2}{3}x=\frac{5}{12}\)
\(x.\left(\frac{1}{2}-\frac{2}{3}\right)=\frac{5}{12}\)
\(\Rightarrow x=-\frac{5}{2}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
`(3x-5)^4=256`
`=>(3x-5)^4=(4)^4=(-4)^4`
`=>[(3x-5=4),(3x-5=-4):}`
`=>[(3x=9),(3x=1):}`
`=>[(x=3),(x=1/3):}`
Vậy `x=3` hoặc `x=1/3.`
Ta có: \(\left(3x-5\right)^4=256\)
\(\Leftrightarrow\left[{}\begin{matrix}3x-5=4\\3x-5=-4\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}3x=9\\3x=1\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=3\\x=\dfrac{1}{3}\end{matrix}\right.\)
\(\frac{1}{2}x-\frac{2}{3}x=\frac{5}{12}\Leftrightarrow\frac{-1}{3}x=\frac{5}{12}\Leftrightarrow x=-\frac{5}{4}\)