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a: \(\dfrac{5}{3}\cdot\dfrac{7}{10}=\dfrac{5}{10}\cdot\dfrac{7}{3}=\dfrac{14}{3}>2\)
\(\dfrac{5}{7}:\dfrac{7}{10}=\dfrac{5}{7}\cdot\dfrac{10}{7}=\dfrac{50}{49}< 2\)
=>\(\dfrac{5}{3}\cdot\dfrac{7}{10}>\dfrac{5}{7}:\dfrac{7}{10}\)
b: \(\dfrac{4}{5}\cdot\dfrac{5}{6}=\dfrac{4}{6}=\dfrac{2}{3}\)
\(\dfrac{8}{9}:\dfrac{4}{3}=\dfrac{8}{9}\cdot\dfrac{3}{4}=\dfrac{8}{4}\cdot\dfrac{3}{9}=\dfrac{2}{3}\)
Do đó: \(\dfrac{4}{5}\cdot\dfrac{5}{6}=\dfrac{8}{9}:\dfrac{4}{3}\)
c: \(\dfrac{5}{11}\cdot\dfrac{33}{15}=\dfrac{5}{15}\cdot\dfrac{33}{11}=\dfrac{3}{3}=1\)
\(\dfrac{6}{17}\cdot\dfrac{34}{25}=\dfrac{34}{17}\cdot\dfrac{6}{25}=2\cdot\dfrac{6}{25}=\dfrac{12}{25}< 1\)
=>\(\dfrac{5}{11}\cdot\dfrac{33}{15}>\dfrac{6}{17}\cdot\dfrac{34}{25}\)
d: \(\dfrac{15}{19}\cdot\dfrac{38}{5}=\dfrac{15}{5}\cdot\dfrac{38}{19}=3\cdot2=6\)
\(\dfrac{15}{16}:\dfrac{3}{8}=\dfrac{15}{16}\cdot\dfrac{8}{3}=\dfrac{15}{3}\cdot\dfrac{8}{16}=\dfrac{5}{2}\)<6
=>\(\dfrac{15}{19}\cdot\dfrac{38}{5}>\dfrac{15}{16}:\dfrac{3}{8}\)
33/15 x 35/21 x 63/14 x 9/30
= 11/5 x 5/3 x 9/2 x 3/10
= 99/20
= \(\frac{33}{15}\)x \(\frac{5}{3}\)x \(\frac{9}{2}\)x \(\frac{3}{10}\)
= \(\frac{11}{3}\)x \(\frac{9}{2}\)x \(\frac{3}{10}\)
= \(\frac{33}{2}\)x \(\frac{3}{10}\)
= \(\frac{99}{20}\)
Bài 1:
a: \(=\dfrac{21}{7}\cdot\dfrac{15}{45}\cdot\dfrac{9}{18}=3\cdot\dfrac{1}{3}\cdot\dfrac{1}{2}=\dfrac{1}{2}\)
b: \(=\dfrac{11}{33}\cdot\dfrac{24}{8\cdot12}\cdot\dfrac{27}{9}=\dfrac{24}{96}=\dfrac{1}{4}\)
a)\(x:\frac{9}{22}=44\) b)\(x:\frac{5}{11}=33\) c)\(x:\frac{4}{33}=22\)
\(x\) \(=44\times\frac{9}{22}\) \(x\) \(=33\times\frac{5}{11}\) \(x\) \(=22\times\frac{4}{33}\)
\(x\) \(=18\) \(x\) \(=15\) \(x\) \(=\frac{8}{3}\)
A) X : 9/22 = 44
X=44x9/22
X=18
B) X : 5/11 = 33
X=33x5/11
X=15
C) X : 4/33 = 22
X=22x4/33
X=8/3
4/15 + 1/2
= 8/30 + 15/30
= 23/30
51/9 - 2/3
= 51/9 - 6/9
= 45/9
= 5
3/4 × 15/26
= 45/104
7/3 : 5/14
= 7/3 × 14/5
= 98/15
\(\frac{9\times11\times36}{33\times27\times18}=\frac{1\times1\times2}{3\times3\times1}=\frac{2}{9}\)
\(\frac{9\cdot11\cdot36}{33\cdot27\cdot18}=\frac{9\cdot11\cdot2\cdot18}{3\cdot11\cdot3\cdot9\cdot18}=\frac{2}{9}\)
Chu'c hok to^'t nha!
tách mỗi thừa số ra
a,\(\frac{3\cdot3\cdot5\cdot3\cdot11\cdot2}{3\cdot10\cdot3\cdot3\cdot11\cdot4}=\frac{1}{10}\)