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a) \(x=10\)
b) \(x=11\)
Nhớ k cho mình với nhá, chúc bạn may mắn!
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a: 7x+58=100
nên 7x=42
hay x=6
c: x-56:x=16
nên x-14=16
hay x=30
c)x - 56 : 4 = 16
x - 56 = 16 : 4
x- 56 = 4
x =4 + 56
x = 60
d)101 + (36 - 4x) = 105
(36- 4x ) = 105 - 101
36 - 4x = 4
4x = 36 - 4
4x = 32
x = 32:4
x = 8
![](https://rs.olm.vn/images/avt/0.png?1311)
Bài 2:a, x+17=109
x =109-17
x =92
b,x+34=56+42+43
x+34=141
x =141-34
x =107
c,2x+45=x+94
2*x =x+94-45
x+x =x+49
suy ra x=49
d,x+109=1+2+3+........+99
x+109=495
x =495-109
x =386
Bài 1 mik ko có làm được.
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a) \(2^x.4=128\)
\(2^x=128:4\)
\(2^x=32\)
\(2^x=2^5\)
\(\Rightarrow x=5\)
vay \(x=5\)
b) \(\left(2x+1\right)^3=125\)
\(\left(2x+1\right)^3=5^3\)
\(\Rightarrow2x+1=5\)
\(\Rightarrow2x=4\)
\(\Rightarrow x=2\)
vay \(x=2\)
![](https://rs.olm.vn/images/avt/0.png?1311)
a) 305 - 5x = 290
5.(61-x) = 290
61-x = 58
x = 3
b) (3x - 24) .25 = 26
3x - 24 = 2
3x = 18
x=6
c) 8 + 3.(x-5)2 = 35
3.(x-5)2 = 27
(x-5)2 = 9 = 32 = (-3)2
=> x - 5 = 3 => x = 8
x-5 = - 3 => x = 2
KL:>.
d) 21 chia hết cho x - 2
\(\Rightarrow x-2\inƯ_{\left(21\right)}=\left\{\pm1;\pm3;\pm7;\pm21\right\}.\)
..
rùi bn tự lập bảng xét giá trị nhé
![](https://rs.olm.vn/images/avt/0.png?1311)
\(a,x\left(y-2\right)=8\\ \Rightarrow x;\left(y-2\right)\inƯ\left(8\right)=\left\{-8;-4;-2;-1;1;2;4;8\right\}\)
\(x\) | \(-8\) | \(-4\) | \(-2\) | \(-1\) | \(1\) | \(2\) | \(4\) | \(8\) |
\(y-2\) | \(-1\) | \(-2\) | \(-4\) | \(-8\) | \(8\) | \(4\) | \(2\) | \(1\) |
\(y\) | \(1\) | \(0\) | \(-2\) | \(-6\) | \(10\) | \(6\) | \(4\) | \(3\) |
Vậy \(\left(x;y\right)=\left(-8;1\right),\left(-4;0\right),\left(-2;-2\right),\left(-1;-6\right),\left(2;6\right),\left(4;4\right),\left(8;3\right)\)
\(b,\left(x-1\right)\left(y-2\right)=9\\ \Rightarrow\left(x-1\right),\left(y-2\right)\inƯ\left(9\right)=\left\{-9;-3;-1;1;3;9\right\}\)
\(x-1\) | \(-9\) | \(-3\) | \(-1\) | \(1\) | \(3\) | \(9\) |
\(y-2\) | \(-1\) | \(-3\) | \(-9\) | \(9\) | \(3\) | \(1\) |
\(x\) | \(-8\) | \(-2\) | \(0\) | \(2\) | \(4\) | \(10\) |
\(y\) | \(1\) | \(-1\) | \(-7\) | \(11\) | \(5\) | \(3\) |
Vậy \(\left(x;y\right)=\left(-8;1\right),\left(-2;-1\right),\left(0;-7\right),\left(2;11\right),\left(4;5\right),\left(10;3\right)\)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\Leftrightarrow2^x\cdot\dfrac{1}{8}+2^x\cdot\dfrac{1}{4}+2^x\cdot\dfrac{1}{2}=254\)
\(\Leftrightarrow2^x\cdot\dfrac{7}{8}=254\)
\(\Leftrightarrow2^x=\dfrac{2032}{7}\)
mà x là số tự nhiên
nên \(x\in\varnothing\)
a) x= 2
b) x= 4
c) x= 2
d) {x+1}^2 = 25
{x+1}^2 = 5^2
x+1=5
x= 5 -1 =4