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trả lời
\(\frac{2^{10}.13.2^{10}.65}{28.104}\)=\(\frac{2^{20}.13^2.5}{2^5.7.13}=\frac{2^{15}.13.5}{7}\)
nếu thấy đúng thì tích
nếu sai thì thì thôi
\(2^{10}.13+2^{10}.65:2^8.104=2^{10}.78:2^8.104=2^2.78.104=4.78.104=32448\)
a,10x+65=125
10x =125-65
x =60:10
x =6
Vậy:...
b,45-(5-2x)^3=2.3^2
45-(5-2x)^3=18
(5-2x)^3 =45-18
(5-2x)^3 =27=3^3
=> 5-2x = 3
2x = 5-3
x= 2:2
x=1
Vậy:....
-Hok tốt ~ K mk nhak.
a, 10x + 65 = 125
10x = 125 - 65
10x = 60
x = 60 : 10
x = 6
b,45-(5-2x)^3=2.3^2
45 - ( 5 - 2x )^3 =18
(5 - 2x)^3 = 45 - 18
(5 - 2x )^3= 3^3
5 - 2x = 3
2x = 2
x = 1
c,2(x-3)-12=(-10)
2x - 6 -12 =-10
2x = -10 + 6 + 12
2x = 8
x = 4
d,x-12=(-13)+1+|-13|
x - 12 = -13 + 1 + 13
x - 12 = 1
x = 13
hok tốt!!!
\(A=\frac{2^{10}.13+2^{10}.65}{2^8.104}=\frac{2^{10}.\left(13+65\right)}{2^8.104}=\frac{2^{10}.78}{2^8.104}=3\)
\(A=\frac{2^{10}.13+2^{10}.65}{2^8.104}=\frac{2^{10}\left(13+65\right)}{2^8.104}=\frac{2^{10}.78}{2^8.104}=\frac{2^2.78}{104}=\frac{2^2.2.39}{2^3.13}=\frac{2^3.39}{2^3.13}=3\)
\(\frac{2^{10}.13+2^{10}.65}{2^8.104}\)
Xét : 210 . 13 + 210. 65 = 210 . ( 13 + 65 ) = 210 . 78
28 . 104 = 28 . ( 22 . 26 ) = 28. 22. 26 = 210.26
có : \(\frac{2^{10}.13+2^{10}.65}{2^8.104}\)= \(\frac{2^{10}.78}{2^{10}.26}\)= \(\frac{78}{26}\)= 3
\(\frac{2^{10}.13+2^{10}.65}{2^8.104}=\frac{2^{10}.\left(13+65\right)}{2^8.104}=\frac{2^{10}.78}{2^8.104}\)
\(=\frac{2^2.39}{52}=\frac{2^2.39}{2^2.13}\)
\(=\frac{39}{13}\)
\(=3\)
a)
\(4^{10}\cdot8^{15}=2^{20}\cdot2^{45}=2^{65}\)
b)
\(27^{16}\cdot9^{10}=3^{48}\cdot3^{20}=3^{68}\)
a) 410 . 815 = (22)10 . (23)15 = 220 . 245 = 265
b) 2716 . 910 = (33)16 .(32)10=348 . 320 = 368
c) \(\frac{2^{10}\cdot13+2^{10}\cdot65}{28\cdot104}=\frac{2^{10}\cdot13\cdot\left(1+5\right)}{2^5\cdot7\cdot13}=\frac{2^5\cdot6}{7}=\frac{192}{7}\)