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a= (\(\frac{2}{5}\)+\(\frac{2}{9}\)+\(\frac{2}{11}\)\(\times\)\(\frac{5}{7}\)\(+\frac{7}{9}\)\(+\frac{7}{11}\)\()\)
Câu b:
\(\frac{21}{8}:\frac{5}{6}+\frac{1}{2}:\frac{5}{6}\)
= \(\frac{63}{20}+\frac{3}{5}\)
= \(\frac{15}{4}\)
\(\left(\frac{21}{8}+\frac{1}{2}\right):\frac{5}{6}\)
\(\frac{25}{8}:\frac{5}{6}\)
\(\frac{25}{8}.\frac{6}{5}\)
\(\frac{30}{8}\)
rồi, h thì dễ hỉu @@
\(\left(\frac{74}{7}+\frac{19}{5}\right)-\left(\frac{39}{7}-\frac{6}{5}\right)=\frac{74}{7}+\frac{19}{5}-\frac{39}{7}+\frac{6}{5}=\left(\frac{74}{7}-\frac{39}{7}\right)+\left(\frac{19}{5}+\frac{6}{5}\right)=\frac{35}{7}+\frac{25}{5}=5+5=10\)
Bài 2:
\(B=\left(1-\frac{1}{2}\right).\left(1-\frac{1}{3}\right).\left(1-\frac{1}{4}\right).......\left(1-\frac{1}{2004}\right)\)
\(=\frac{1}{2}.\frac{2}{3}.\frac{3}{4}....\frac{2003}{2004}\)
\(=\frac{1}{2004}\)
\(2011,2012\times2000\times\left(\frac{5}{6}-\frac{1}{3}-50\%\right)\times1234+10\)
\(=2011,2012\times2000\times\left(\frac{5}{6}-\frac{1}{3}-\frac{50}{100}\right)\times1234+10\)
\(=2011,2012\times2000\times\left(\frac{5}{6}-\frac{1}{3}-\frac{1}{2}\right)\times1234+10\)
\(=2011,2012\times2000\times\left(\frac{5}{6}-\frac{2}{6}-\frac{3}{6}\right)\times1234+10\)
\(=2011,2012\times2000\times0\times1234+10\)
\(=0+10\)
\(=10\)
_Chúc bạn học tốt_
\(2011,2012.2000.\left(\frac{5}{6}-\frac{1}{3}-50\%\right).1234+10\)
\(=2011,2012.2000.\left(\frac{5-2-3}{6}\right).1234+10\)
\(=2011,2012.2000.0.1234+10\)
\(=0+10\)
\(=0 \)