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Trả lời:
Đổi đơn vị:
600Kg= \(\frac{3}{5}\)Tấn
=> Xe tải nặng: 2-\(\frac{3}{5}\)=\(\frac{7}{5}\)=(1\(\frac{2}{5}\))tấn (Chọn C)
1.Đổi 600 kg = \(\frac{3}{5}\)tấn .
Vậy chiếc xe tải nặng số kg là :
2 - \(\frac{3}{5}\)=\(\frac{7}{5}\)(tấn)
Khối lượng của 30 bao gạo tẻ là:
30 x 40 = 1200 ( kg )
Khối lượng của 40 bao gạo nếp là:
40 x 20 = 800 ( kg )
Đổi : 1200 kg = 1,2 tấn
800 kg = 0,8 tấn
Xe đó chở được số tấn gạo là:
1,2 + 0,8 = 2 ( tấn )
Đáp số : 2 tấn gạo
Xe đó chở \(30\times40+40\times20=1200+800=2000\left(kg.gạo\right)=2\left(tấn.gạo\right)\)
Khối lượng của 30 bao gạo tẻ là:
30 x 40 = 1200 ( kg )
Khối lượng của 40 bao gạo nếp là:
40 x 20 = 800 ( kg )
Đổi : 1200 kg = 1,2 tấn
800 kg = 0,8 tấn
Xe đó chở được số tấn gạo là:
1,2 + 0,8 = 2 ( tấn )
Đáp số : 2 tấn gạo
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Số kg gạo tẻ là:
30.40=1200 (kg)
Số gạo nếp là:
40.20=800 (kg)
Xe chở số tấn gạo là:
800+1200=2000(kg)
2000 kg=2 tấn
Đáp số : 2 tấn
a) 30 bao gạo tẻ cân nặng 30 x 40 =1200 (kg)
40 bao gạo nếp cân nặng 40 x 20 = 800 (kg)
Khối lượng gạo xe đó chở là 1200 + 800 = 2000 (kg)
Đổi 2000kg = 2 tấn
b) Đổi 13km500m = 13500m
Hiệu số phần bằng nhau là 5 - 2 = 3 (phần)
Độ dài đoạn đường AC là 13500 : 3 x 2 = 9000 (m)
Độ dài đoạn đường CB là 13500 + 9000 = 22500 (m)
Độ dài đoạn đường AB là 9000 + 22500 = 31500 (m)
a) 30 bao gạo tẻ cân nặng 30 x 40 =1200 (kg)
40 bao gạo nếp cân nặng 40 x 20 = 800 (kg)
Khối lượng gạo xe đó chở là 1200 + 800 = 2000 (kg)
Đổi 2000kg = 2 tấn
b) Đổi 13km500m = 13500m
Hiệu số phần bằng nhau là 5 - 2 = 3 (phần)
Độ dài đoạn đường AC là 13500 : 3 x 2 = 9000 (m)
Độ dài đoạn đường CB là 13500 + 9000 = 22500 (m)
Độ dài đoạn đường AB là 9000 + 22500 = 31500 (m)
Giải :
Đổi : \(600\text{ kg}=\frac{3}{5}\text{ tấn}\)
Xe tải nặng là :
\(2-\frac{3}{5}=\frac{7}{5}\left(=1\frac{2}{5}\right)\text{tấn}\)
=> Chọn C
~HT~