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11 + 22 + ( \(x\) x 2 + \(x\) x 199 ) : 33 = 123 x 123
33 + \(x\) ( 2 + 199) : 33 = 15129
201\(x\) : 33 = 15129 - 33
201\(x\) : 33 = 15096
201\(x\) = 15096 x 33
201\(x\) = 498168
\(x\) = 498168 : 201
\(x\) = 166056/67
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\(\dfrac{-7}{11}=\dfrac{x}{22}\Rightarrow\dfrac{-14}{22}=\dfrac{x}{22}\Rightarrow x=-14\)
\(\dfrac{-5}{11}=\dfrac{x}{33}\Rightarrow\dfrac{-15}{33}=\dfrac{x}{33}\Rightarrow x=-15\)
\(\dfrac{-7}{11}\)=\(\dfrac{x}{22}\)\(\Rightarrow\)11x=-7.22\(\Rightarrow\)11x=-154\(\Rightarrow\)x=-154:11=-14
\(\dfrac{-5}{11}\)=\(\dfrac{x}{33}\)\(\Rightarrow\)11x=-5.33\(\Rightarrow\)11x=-165\(\Rightarrow\)x=-165:11=-15
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A = ( 15/22 - 2/22 ) : 1/33 - ( 6/84 - 8/84) : 1/35 + 1 + 1/5 . ( 3/12 - 2/12 - 12/12 ) . 5/11
A = 13/22 . 33 - (-1/42) . 35 + 1 + 1/5 . - 11/12 . 5/11
A = 39/2 - ( -5/6 ) + 1 + - 11/60 .5/11
A = 39/2 + 5/6 + 1 + (- 1/12)
A = 234/12 + 10 /12 + 12/12 + (-1/12)
A = 255/12
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\(A=\dfrac{1}{3}+\dfrac{1}{3^2}+\dfrac{1}{3^3}+\dfrac{1}{3^4}+...+\dfrac{1}{3^{99}}\)
\(\Rightarrow\dfrac{A}{3}=\dfrac{1}{3^2}+\dfrac{1}{3^3}+\dfrac{1}{3^4}+...+\dfrac{1}{3^{100}}\)
\(\Rightarrow A-\dfrac{A}{3}=\dfrac{2A}{3}=\left(\dfrac{1}{3}+\dfrac{1}{3^2}+\dfrac{1}{3^3}+...+\dfrac{1}{3^{99}}\right)-\left(\dfrac{1}{3^2}+\dfrac{1}{3^3}+\dfrac{1}{3^4}+...+\dfrac{1}{3^{100}}\right)\)
\(\Rightarrow\dfrac{2A}{3}=\left(\dfrac{1}{3^2}-\dfrac{1}{3^2}\right)+\left(\dfrac{1}{3^3}-\dfrac{1}{3^3}\right)+...+\left(\dfrac{1}{3^{99}}-\dfrac{1}{3^{99}}\right)+\left(\dfrac{1}{3}-\dfrac{1}{3^{100}}\right)=\dfrac{1}{3}-\dfrac{1}{3^{100}}\)
\(\Rightarrow2A=3\cdot\left(\dfrac{1}{3}-\dfrac{1}{3^{100}}\right)\)
\(\Rightarrow\text{A}=\dfrac{1-\dfrac{1}{3^{99}}}{2}\)
\(\Rightarrow A=\dfrac{1}{2}-\dfrac{1}{2.3^{99}}< \dfrac{1}{2}\)
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\(\dfrac{-11}{22}\).\(\dfrac{-4}{33}\).\(\dfrac{84}{-25}\).\(\dfrac{5}{8}\)=\(\dfrac{-7}{18}\)
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Bài 1:
\(A=\left(\frac{-5}{11}+\frac{7}{22}-\frac{4}{33}-\frac{5}{44}\right):\left(38\frac{1}{122}-39\frac{7}{22}\right)\)
\(=\frac{-49}{132}:\left(-\frac{879}{671}\right)=\frac{2989}{105408}\)
Bài 2:
\(\frac{4}{5}-\left(\frac{-1}{8}\right)=\frac{7}{8}-x\)
<=> \(\frac{7}{8}-x=\frac{27}{40}\)
<=> \(x=\frac{7}{8}-\frac{27}{40}=\frac{1}{5}\)
Vậy...
11 x 11 = ( 1 + 1 ) x ( 1 + 1 ) = 2 x 2 = 4
22 x 22 = ( 2 + 2 ) x ( 2 + 2 ) = 4 x 4 = 16
33 x 33 = ( 3 + 3 ) x ( 3 + 3 ) = 6 x 6 = 36
Đáp án 1 : 36
11 x11 = ( 1 + 1 ) x ( 1 + 1 ) = 2 x 2 = 4
22 x 22 = ( 2 + 2 ) x ( 2 + 2 ) = 4 x 4 = 16
33 x 33 = ( 3 + 3 ) x ( 3 + 3 ) = 6 x 6 =36
Đáp án 2 : 28
11 x 11 = 11 + ( 1 + 1 ) - 9 = 4
22 x 22 = 22 + ( 2 + 2 ) - 10 = 16
33 x 33 = 33 + ( 3 + 3 ) - 11 = 28
Còn nhiều đáp án khác nữa nhé