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8 tháng 7 2018

\(P=\frac{0,75-0,6+\frac{3}{7}+\frac{3}{13}}{2,75-2,2+\frac{11}{7}+\frac{11}{13}}\)

\(\Rightarrow P=\frac{\frac{3}{4}-\frac{3}{5}+\frac{3}{7}+\frac{3}{13}}{\frac{11}{4}-\frac{11}{5}+\frac{11}{7}+\frac{11}{13}}\)

\(\Rightarrow P=\frac{3\left(\frac{1}{4}-\frac{1}{5}+\frac{1}{7}+\frac{1}{13}\right)}{11\left(\frac{1}{4}-\frac{1}{5}+\frac{1}{7}+\frac{1}{13}\right)}\)

\(\Rightarrow P=\frac{3}{11}\)

Vậy \(P=\frac{3}{11}\)

8 tháng 7 2018

Bài 1:

\(P=\frac{0,75-0,6+\frac{3}{7}+\frac{3}{13}}{2,75-2,2+\frac{1}{7}+\frac{11}{13}}\)

\(=\frac{\frac{3}{4}-\frac{3}{5}+\frac{3}{7}+\frac{3}{13}}{\frac{11}{4}-\frac{11}{5}+\frac{11}{7}-\frac{11}{3}}\)

\(=\frac{3.\left(\frac{1}{4}-\frac{1}{5}+\frac{1}{7}-\frac{1}{13}\right)}{11.\left(\frac{1}{4}-\frac{1}{5}+\frac{1}{7}-\frac{1}{13}\right)}=\frac{3}{11}\)

Bài 2:

a) \(\left(x+1\right)\left(x-2\right)< 0\Leftrightarrow\orbr{\begin{cases}\left(x+1\right)=0\left(\text{loại}\right)\\\left(x-2\right)=0\end{cases}}\Rightarrow x=2\)

23 tháng 8 2016

\(\Rightarrow P=\frac{\frac{3}{4}-\frac{3}{5}+\frac{3}{7}+\frac{3}{13}}{\frac{11}{4}-\frac{11}{5}+\frac{11}{7}+\frac{11}{13}}\)

\(\Rightarrow P=\frac{3\left(\frac{1}{4}-\frac{1}{5}+\frac{1}{7}+\frac{1}{13}\right)}{11\left(\left(\frac{1}{4}-\frac{1}{5}+\frac{1}{7}+\frac{1}{13}\right)\right)}\)

\(\Rightarrow P=\frac{3}{11}\)

3 tháng 7 2017

\(P=\frac{0,75-0,6+\frac{3}{7}+\frac{3}{13}}{2,75-2,2+\frac{11}{7}+\frac{11}{13}}\)

\(P=\frac{\frac{3}{4}-\frac{3}{5}+\frac{3}{7}+\frac{3}{13}}{\frac{11}{4}-\frac{11}{5}+\frac{11}{7}+\frac{11}{13}}\)

\(P=\frac{3.\left(\frac{1}{4}-\frac{1}{5}+\frac{1}{7}+\frac{1}{13}\right)}{11.\left(\frac{1}{4}-\frac{1}{5}+\frac{1}{7}-\frac{1}{13}\right)}\)

\(P=\frac{3}{11}\)

3 tháng 7 2017

\(P=\frac{0,75-0,6+\frac{3}{7}+\frac{3}{13}}{2,75-2,2+\frac{11}{7}+\frac{11}{13}}\)

\(P=\frac{0,15+3\times\left(\frac{1}{7}+\frac{1}{13}\right)}{0,55+11\times\left(\frac{1}{7}+\frac{1}{13}\right)}\)

\(P=\frac{0,05\times3+3\times\left(\frac{1}{7}+\frac{1}{13}\right)}{0,05\times11+11\times\left(\frac{1}{7}+\frac{1}{13}\right)}\)

\(P=\frac{3\times\left(0,05+\frac{1}{7}+\frac{1}{13}\right)}{11\times\left(0,05+\frac{1}{7}+\frac{1}{13}\right)}\)

\(P=\frac{3}{11}\)

Ta có: \(A=\frac{0,75-0,6+\frac{3}{7}+\frac{3}{13}}{2,75-2,2+\frac{11}{7}+\frac{11}{3}}=\frac{\frac{3}{4}-\frac{3}{5}+\frac{3}{7}+\frac{3}{13}}{\frac{11}{4}-\frac{11}{5}+\frac{11}{7}+\frac{11}{3}}=\frac{3\left(\frac{1}{4}-\frac{1}{5}+\frac{1}{7}+\frac{1}{3}\right)}{11\left(\frac{1}{4}-\frac{1}{5}+\frac{1}{7}+\frac{1}{3}\right)}=\frac{3}{11}\)

1 tháng 7 2016

\(P=\frac{0.75-0.6+\frac{3}{7}+\frac{3}{13}}{2.75-2.2+\frac{11}{7}+\frac{11}{3}}\)

\(P=\frac{\frac{3}{4}-\frac{3}{5}+\frac{3}{7}+\frac{3}{13}}{\frac{11}{4}-\frac{11}{5}+\frac{11}{7}+\frac{11}{13}}\)

\(P=\frac{3\left(\frac{1}{4}-\frac{1}{5}+\frac{1}{7}+\frac{1}{15}\right)}{11\left(\frac{1}{4}-\frac{1}{5}+\frac{1}{7}+\frac{1}{15}\right)}\)

\(P=\frac{3}{11}\)

4 tháng 7 2016

\(P=\frac{0,75-0,6+\frac{3}{7}+\frac{3}{13}}{2,75-2,2+\frac{11}{7}+\frac{11}{13}}\)\(=\frac{\frac{3}{4}-\frac{3}{5}+\frac{3}{7}+\frac{3}{13}}{\frac{11}{4}-\frac{11}{5}+\frac{11}{7}+\frac{11}{13}}\)\(=\frac{3.\left(\frac{1}{4}-\frac{1}{5}+\frac{1}{7}+\frac{1}{13}\right)}{11.\left(\frac{1}{4}-\frac{1}{5}+\frac{1}{7}+\frac{1}{13}\right)}\)\(=\frac{3}{11}\)

3 tháng 7 2016

Tính nhanh \(A=\frac{0,75+0,6-\frac{3}{7}-\frac{3}{13}}{2,75+2,2-\frac{11}{7}-\frac{11}{13}}\)