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5) 125. (−8). (−25). 9.4.1000 : 3
=[125.(-8)].[(-25).4].(9:3).1000
=-1000.(-100).3.1000
=100000.3.1000
=300000.1000
=300000000
6) (−2)3 . 13.125
=-8.13.125
=(-8.125).13
=-1000.13
=-13000
7) 17. (38 − 5) − 38. (17 − 1)
=17 . 33 - 38 . 16
=561-608
=-47
8) (−41). 135 + 135. (−58) − 135
=(-41).135+135.(-58)+135.(-1)
=135.[-41+(-58)+(-1)]
=135.(-100)
=-13500
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\(\left(1+3+5+7+........+2001\right)\cdot\left(135135\cdot137-135\cdot137137\right)\)
\(=\left(1+3+5+..........+2001\right)\cdot\left(18513495-18513495\right)\)
\(=\left(1+3+5+7+....+2001\right)\cdot0\)
\(=0\)
( 1 + 3 + 5 + 7 + ..... + 2001).(135 135.137 - 135.137 137)
= ( 1 + 3 + 5 + 7 + ..... + 2001).( 135 x 1001 x 137 - 135 x 137 x 1001 )
= ( 1 + 3 + 5 + 7 + ..... + 2001). 0
= 0
k mik nha
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\(\left(2018-\frac{2}{135}+\frac{1}{50}\right)-\left(1-\frac{7}{135}+\frac{4}{50}\right)-\left(5+\frac{5}{135}+\frac{3}{50}\right)\)
\(=2018-\frac{2}{135}+\frac{1}{50}-1+\frac{7}{135}-\frac{4}{50}-5-\frac{5}{135}-\frac{3}{50}\)
\(=2012-\frac{6}{50}\)
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7: \(=-47\cdot100+53\cdot\left(-100\right)=100\cdot\left(-100\right)=-10000\)
8: \(=30\cdot\left(-4\right)-24\cdot30=30\cdot\left(-28\right)=-840\)
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1) tính nhanh
Ta thấy các số cách nhau 2 đơn vị lên
Số số hạng là \(\left(51-3\right)\div2+1=25\) ( số hạng )
Tổng dãy số trên là \(\left(51+3\right)\times25\div2=675\)
2) Tìm x
a) \(135+x\times2=151\)
\(x\times2=151-135=16\)
\(x=16\div8\)
b) \(x\times5-227=273\)
\(x\times5=273+227=500\)
\(x=500\div5\)
\(x=100\)
c) \(\left(x-4\right)\times3+2=101\)
\(\left(x-4\right)\times3=101-2=99\)
\(x-4=99\div3=33\)
\(x=33+4\)
\(x=37\)
d) \(170-\left(4+5\times x\right)=101\)
\(4+5\times x=170-101=69\)
\(5\times x=69-4\)
\(5\times x=65\)
\(x=65\div5\)
\(x=13\)
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( 1 + 3 + 5 + ... + 2002) x ( 135135 x 137 - 135 x 137137)
=( 1 +3 + 5 +... +2002) x ( 135 . 1 001 x 137 - 135x1001 x137)
= ( 1 + 3 + 5 +... +2002) x 0
= 0
\(\left(1+3+5+7+...+2002\right)\times\left(135135\times137-135\times137137\right)\))
Mà giá trị của vế 2 =0
Số nào nhân với 0 cũng bằng 0
=>Giá trị biểu thức =0
![](https://rs.olm.vn/images/avt/0.png?1311)
Ta có: \(\left(2008-\dfrac{2}{135}+\dfrac{1}{50}\right)-\left(1-\dfrac{7}{135}+\dfrac{4}{150}\right)-\left(5+\dfrac{5}{135}+\dfrac{3}{50}\right)\)
= \(2008-\dfrac{2}{135}+\dfrac{1}{50}-1+\dfrac{7}{135}-\dfrac{4}{150}-5-\dfrac{5}{135}-\dfrac{3}{50}\)
= (2008-1-5) + \(\left(\dfrac{1}{50}-\dfrac{3}{50}\right)-\left(\dfrac{2}{135}-\dfrac{7}{135}\right)-\dfrac{4}{150}\)
=2002 \(-\dfrac{1}{25}\)+\(\dfrac{1}{27}\)\(-\dfrac{4}{150}\)
=2001,9(3)
![](https://rs.olm.vn/images/avt/0.png?1311)
Ta có:
60 = 2^2 .3.5; 90 = 2.3^2.5; 135 = 3^3 .5
<-> ƯCLN(60, 90, 135) = 3.5 = 15.
ƯC(60, 90, 135) = Ư(15) = {1, 3, 5, 15}
--thoT-T--
\(60=2^2.3.5\)
\(90=2.3^2.5\)
\(135=3^3.5\)
\(\Rightarrow ƯCLN(60;90;135)=3.5=15\)
\(\left(135-7\right)\times5-135\times5+35\)
\(=135\times5-7\times5-135\times5+35\)
\(=135\times\left(5-5\right)-35+35\)
\(=0+0=0\)
\(\left(135-7\right).5-135.5+35\)
\(=\left(135-7-135\right).5+35\)
\(=-7.5+35\)
\(=0\)