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1.a) Dễ nhận thấy đề toán chỉ giải được khi đề là tìm x,y. Còn nếu là tìm x ta nhận thấy ngay vô nghiệm. Do đó: Sửa đề: \(\left|x-3\right|+\left|2-y\right|=0\)
\(\Leftrightarrow\left|x-3\right|=\left|2-y\right|=0\)
\(\left|x-3\right|=0\Rightarrow\left\{{}\begin{matrix}x-3=0\\-\left(x-3\right)=0\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x=3\\x=-3\end{matrix}\right.\) (1)
\(\left|2-y\right|=0\Rightarrow\left\{{}\begin{matrix}2-y=0\\-\left(2-y\right)=0\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}y=2\\y=-2\end{matrix}\right.\) (2)
Từ (1) và (2) có: \(\left[{}\begin{matrix}\left\{{}\begin{matrix}x_1=3\\x_2=-3\end{matrix}\right.\\\left\{{}\begin{matrix}y_1=2\\y_2=-2\end{matrix}\right.\end{matrix}\right.\)
\(a,30\cdot6+30\cdot71+20\cdot30\)
=\(30\cdot\left(6+71+20\right)\)
=\(30\cdot97=2910\)
\(b,24\cdot\left(31+119\right)+76\cdot\left(29+121\right)\)
=\(24\cdot150+76\cdot150\)
=\(150\cdot\left(24+76\right)\)
=\(150\cdot100\)
=\(15000\)
\(c,87\cdot23+70\cdot87+43\cdot93\)
=\(87\cdot\left(23+87\right)+43\cdot93\)
=\(87\cdot110+3999\)
=\(9570+3999\)
=13569
a) 15 . 6 . 2 + 3 . 71 . 10 + 20 . 30
= ( 15 . 2 ) . 6 + ( 3 . 10 ) . 71 + 20 . 30
= 30 . 6 + 30 . 71 + 20 . 30
= 30 . ( 6 + 71 + 30 )
= 30 . 107
= 3210
b) 24 . 31 + 24 . 119 + 76 . 29 + 76 . 121
= 24 . ( 31 + 119 ) + 76 . ( 29 + 121 )
= 24 . 150 + 76 . 150
= 150 . ( 24 + 76 )
= 150 . 100
= 15 000
c) 87 . 23 + 43 . 93 + 70 . 87
= 87 . 23 + 70 . 87 + 43 . 93
= 87 . ( 23 + 70 ) + 43 . 93
= 87 . 93 + 43 . 93
= 93 . ( 87 + 43 )
= 93 . 130
= 12 090
35 . 23 .+ 35 . 41 + 64 . 65 =35(23+41)+64.65=35.64+64.65=64(35+65)=64.100=6400
29 . 87 - 29 . 23 + 64 . 71 =29(87-23)+64.71=29.64+64.71=64(29+71)=29.100=2900
27 . 121 - 87 . 27 + 73 . 34 =27(121-87)+73.34=27.34+73.34=34(27+73)=34.100=3400
35 . 23 + 35 . 41 + 64 . 65 29 . 87 - 29 . 23 + 64 . 71
= 35 . ( 23 + 41 ) + 64 . 65 = 29 . ( 87 - 23 ) + 64 . 71
= 35 . 64 + 64 . 65 = 29 . 64 + 64 . 71
= 64 . ( 35 + 65 ) = 64 . ( 29 + 71 )
= 64 . 100 = 64 . 100
= 6400 = 6400
27 . 121 - 87 . 27 + 73 . 34
= 27 . ( 121 - 87 ) + 73 . 34
= 27 . 34 + 73 . 34
= 34 . ( 27 + 73 )
= 34 . 100
= 3400
Đó chính là câu trả lời bạn nhớ tích cho mình nhé
1) $(-35)\cdot18+28\cdot35$
$=35\cdot(-18)+28\cdot35$
$=35\cdot(-18+28)$
$=35\cdot10$
$=350$
2) $53\cdot29-47\cdot(-29)$
$=53\cdot29-47\cdot(-1)\cdot29$
$=53\cdot29+47\cdot29$
$=29\cdot(53+47)$
$=29\cdot100$
$=2900$
3) $125\cdot(-24)+24\cdot225$
$=(-125)\cdot24+24\cdot225$
$=24\cdot(-125+225)$
$=24\cdot100$
$=2400$
4) $26\cdot(-121)-121\cdot(-36)$
$=-121\cdot[26+(-36)]$
$=-121\cdot(26-36)$
$=-121\cdot(-10)$
$=121\cdot10$
$=1210$
5) $65\cdot(-25)+25\cdot(-23)$
$=-65\cdot25+25\cdot(-23)$
$=25\cdot(-65-23)$
$=25\cdot(-88)$
$=-2200$
6) $237\cdot(-26)+26\cdot137$
$=-237\cdot26+26\cdot137$
$=26\cdot(-237+137)$
$=26\cdot(-100)$
$=-2600$
7) $30\cdot(-125)+25\cdot30$
$=30\cdot(-125+25)$
$=30\cdot(-100)$
$=-3000$
8) $(-37)\cdot69+(-31)\cdot37$
$=37\cdot(-69)+37\cdot(-31)$
$=37\cdot(-69-31)$
$=37\cdot(-100)$
$=-3700$
9) $31\cdot72-31\cdot70-31\cdot2$
$=31\cdot(72-70-2)$
$=31\cdot(2-2)$
$=31\cdot0$
$=0$
10) $(-12)\cdot47+(-12)\cdot52+(-12)$
$=-12\cdot(47+52+1)$
$=-12\cdot100$
$=-1200$
$\text{#}Toru$
a)\(\frac{7}{13}.\frac{7}{15}-\frac{5}{12}.\frac{21}{39}+\frac{49}{21}.\frac{8}{15}\)
=\(\frac{7}{13}.\frac{7}{15}-\frac{5}{12}.\frac{7}{13}+\frac{7}{13}.\frac{8}{15}\)
=\(\frac{7}{13}.\left(\frac{7}{15}-\frac{5}{12}-\frac{8}{15}\right)\)
=\(\frac{7}{13}.\frac{7}{12}\)
=\(\frac{49}{156}\)
b)\(\left(\frac{12}{199}+\frac{23}{200}-\frac{34}{201}\right).\left(\frac{1}{2}-\frac{1}{3}-\frac{1}{6}\right)\)
=\(a.\left(\frac{3}{6}-\frac{2}{6}-\frac{1}{6}\right)\)
=a . 0
=0
Bài 2
a)Có
\(3^{200}=3^{2.100}=\left(3^2\right)^{100}=9^{100}\)
\(2^{300}=2^{3.100}=\left(2^3\right)^{100}=8^{100}\)
Vì 8<9 =>\(8^{100}< 9^{100}\) =>\(3^{200}>2^{300}\)
Bài 3:
a) \(abc.1001=abcabc\)
\(abc+1000.abc=abcabc\)
\(abc+abc000=abcabc\)
\(abcabc=abcabc\left(đpcm\right)\)
b) \(1+2+3+...+2000\)
\(=\frac{\left(2000-1\right).2000}{2}\)
\(=1999000\)
Bài 1:
a) \(71-\left(33+x\right)=26\)
\(\Leftrightarrow33+x=45\)
\(\Leftrightarrow x=12\)
Vậy ...
b) \(\left(x+73\right)-26=76\)
\(\Leftrightarrow x+73=102\)
\(\Leftrightarrow x=29\)
Vậy ...
c) \(140:\left(x-8\right)=7\)
\(\Leftrightarrow x-8=20\)
\(\Leftrightarrow x=28\)
Vậy ...
d) \(6x+4x=2010\)
\(\Leftrightarrow10x=2010\)
\(\Leftrightarrow x=201\)
Vậy ...
Gọi C=\(\frac{\frac{2}{39}-\frac{1}{15}-\frac{2}{153}}{\frac{1}{34}+\frac{3}{20}-\frac{3}{26}}:\frac{1+\frac{2}{71}-\frac{5}{121}}{\frac{65}{121}-\frac{26}{71}-13}\)
=\(\frac{\frac{-4}{9}\cdot\left(\frac{1}{34}+\frac{3}{20}-\frac{3}{26}\right)}{-\left(\frac{1}{34}-\frac{3}{20}-\frac{3}{26}\right)}:\frac{1+\frac{2}{71}-\frac{5}{121}}{-13\cdot\left(\frac{2}{71}-\frac{5}{121}+1\right)}\)
=\(-\frac{4}{9}:-\frac{1}{13}=-\frac{4}{9}\cdot\left(-13\right)=\frac{\left(-4\right)\cdot\left(-13\right)}{9}=\frac{52}{9}\)