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a) \(\dfrac{24}{32}=\dfrac{15}{20};\dfrac{32}{24}=\dfrac{20}{15};\dfrac{15}{24}=\dfrac{20}{32};\dfrac{32}{24}=\dfrac{24}{15}\)
b) \(\dfrac{4,8}{25,6}=\dfrac{0,6}{3,2};\dfrac{25,6}{4,8}=\dfrac{3,2}{0,6};\dfrac{25,6}{3,2}=\dfrac{4,8}{0,6};\dfrac{3,2}{25,6}=\dfrac{0,6}{4,8}\)
Lời giải:
a. $\frac{3}{-2}=\frac{9}{-6}$
$\frac{-2}{3}=\frac{-6}{9}$
$\frac{3}{9}=\frac{-2}{-6}$
$\frac{9}{3}=\frac{-6}{-2}$
b.
$\frac{12}{16}=\frac{3}{4}$
$\frac{16}{12}=\frac{4}{3}$
$\frac{12}{3}=\frac{16}{4}$
$\frac{3}{12}=\frac{4}{16}$
Tỉ lệ thức là đẳng thức của hai tỉ số \(\frac{a}{b}=\frac{c}{d}\)
a) \(12.20=15.16\)
\(\Leftrightarrow\)\(\frac{12}{15}=\frac{16}{20}\) ; \(\frac{20}{15}=\frac{16}{12}\);
\(\Leftrightarrow\) \(\frac{12}{16}=\frac{15}{20}\); \(\frac{10}{16}=\frac{15}{12}\)
b) \(\left(a-b\right).\left(a+b\right)=2.3\)
\(\Leftrightarrow\)\(\frac{\left(a-b\right)}{2}=\frac{3}{\left(a+b\right)}\); \(\frac{\left(a-b\right)}{3}=\frac{2}{\left(a+b\right)}\)
\(\Leftrightarrow\)\(\frac{\left(a+b\right)}{3}=\frac{2}{\left(a+b\right)}\); \(\frac{\left(a+b\right)}{2}=\frac{3}{\left(a-b\right)}\)
\(\frac{12}{15}=\frac{16}{20};\frac{12}{16}=\frac{15}{20};\frac{20}{16}=\frac{15}{12};\frac{20}{16}=\frac{15}{12}\)
\(1.\)
\(a,\)
\(7.\left(-28\right)=\left(-49\right).4\)
Ta có : \(\frac{7}{-49}=\frac{4}{-28}\) \(\frac{-28}{4}=\frac{-49}{7}\)
\(\frac{7}{4}=\frac{-49}{-28}\) \(\frac{-28}{-49}=\frac{4}{7}\)
\(b,\)
\(0,36.4,25=0,9.1,7\)
Ta có : \(\frac{0,36}{0,9}=\frac{1,7}{4,25}\) \(\frac{0,36}{1,7}=\frac{0,9}{4,25}\)
\(\frac{4,25}{0,9}=\frac{1,7}{0,36}\) \(\frac{4,25}{1,7}=\frac{0,9}{0,36}\)
a) \(12.20=15.16\)
\(\Rightarrow\frac{12}{15}=\frac{16}{20};\frac{15}{12}=\frac{20}{16};\frac{20}{15}=\frac{16}{12};\frac{12}{16}=\frac{15}{20}\)
b) \(2,4.3,2=8.0,96\)
\(\Rightarrow\frac{2,4}{8}=\frac{0,96}{3,2};\frac{8}{2,4}=\frac{3,2}{0,96};\frac{3,2}{8}=\frac{0,96}{2,4};\frac{2,4}{0,96}=\frac{8}{3,2}\)