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20 tháng 4 2018

1135/23-167/32+330/23

=(1135/23-330/23)+167/32

=805/23+167/32

=35+167/32

=1120/32+167/32

=1287/32

30 tháng 7 2016

  \(=49\frac{8}{23}-5\frac{7}{32}-14\frac{8}{23}\)

\(=\left(49\frac{8}{23}-14\frac{8}{23}\right)-5\frac{7}{32}\)

\(=35\frac{0}{23}-5\frac{7}{32}\)

\(=\frac{805}{23}-\frac{167}{32}\)

\(\frac{25760}{736}-\frac{3841}{736}\)

\(=\frac{21919}{736}=\frac{953}{32}\)

26 tháng 7 2016

A= \(49\frac{8}{23}-\left(5\frac{7}{32}+14\frac{8}{23}\right)\)

=\(\frac{1135}{32}-\left(\frac{167}{32}+\frac{330}{23}\right)\)

=\(\frac{1135}{23}-\frac{167}{32}-\frac{330}{23}\)

=\(\left(\frac{1135}{23}-\frac{330}{23}\right)-\frac{167}{32}\)

=\(\frac{805}{23}-\frac{167}{32}\)

=\(\frac{953}{32}\)

 

26 tháng 7 2016

uk..cảm ơn bạn Trần Quang Hiếu

6 tháng 6 2016

e) \(E=0,7.2\frac{2}{3}.20.0,375.\frac{5}{28}\)

        \(=\left(0,7.20\right)\left(2\frac{2}{3}.0,375\right)\frac{5}{28}\)

        \(=14.1.\frac{5}{28}\)

        \(=14.\frac{5}{28}\)

        \(=\frac{5}{2}\)

f) \(F=\left(9,75.21\frac{3}{7}+\frac{39}{4}.18\frac{4}{7}\right)\frac{15}{78}\)

       \(=\left(\frac{39}{4}.21\frac{3}{7}+\frac{39}{4}.18\frac{4}{7}\right)\frac{15}{78}\)

       \(=\frac{39}{4}\left(21\frac{3}{7}+18\frac{4}{7}\right)\frac{15}{78}\)

       \(=\frac{39}{4}.40.\frac{15}{78}\)

       \(=390.\frac{15}{78}\)

       \(=78\)

Chúc bạn học tốt môn Toán!!!

6 tháng 6 2016

Mình ko ghi đề đâu

\(A=49\frac{8}{23}-5\frac{7}{32}-14\frac{8}{23}=\left(49\frac{8}{23}-14\frac{8}{23}\right)-5\frac{7}{32}=35-5\frac{7}{32}=29\frac{25}{32}\)

\(B=71\frac{38}{45}-43\frac{8}{45}+1\frac{17}{57}=\left(71\frac{38}{45}-43\frac{8}{45}\right)+1\frac{17}{57}=28\frac{2}{3}+1\frac{17}{57}=29\frac{55}{57}\)

\(C=-\frac{3}{7}.\left(\frac{5}{9}+\frac{4}{9}\right)+2\frac{3}{7}=-\frac{3}{7}.1+2\frac{3}{7}=-\frac{3}{7}+2\frac{3}{7}=2\)

10 tháng 5 2018

49\(\frac{8}{23}\) - (5\(\frac{7}{32}\) + 14\(\frac{8}{23}\) )

\(\frac{1135}{23}\) - (\(\frac{167}{32}\) +\(\frac{330}{23}\) )

\(\frac{1135}{23}\) - \(\frac{14401}{736}\) 

=\(\frac{953}{32}\)

10 tháng 5 2018

\(49\frac{8}{23}-\left(5\frac{7}{32}+14\frac{8}{23}\right)\)

\(=\frac{1135}{23}\left(\frac{135}{32}+\frac{330}{23}\right)\)

\(=\frac{1135}{23}.\frac{13665}{736}\)

\(=916,2201678\)

25 tháng 5 2016

\(=49\frac{8}{23}-5\frac{7}{32}-14\frac{8}{23}\)

\(=49\frac{8}{23}-14\frac{8}{23}-5\frac{7}{12}\)

\(=35-5\frac{7}{32}\)

\(=35-\frac{167}{32}\)

\(=\frac{1120}{32}-\frac{167}{32}\)

\(=\frac{935}{32}\)

25 tháng 5 2016

\(49\frac{8}{23}-\left(5\frac{7}{32}+14\frac{8}{23}\right)\)

\(=49\frac{8}{23}-5\frac{7}{32}-14\frac{8}{23}\)

\(=\left(49\frac{8}{23}-14\frac{8}{23}\right)-5\frac{7}{32}\)

\(=35-5\frac{7}{32}\)

\(=35-\frac{167}{32}\)

\(=\frac{953}{32}\)

7 tháng 3 2022

biểu thức đâu

7 tháng 3 2022

biểu thức đó

 

7 tháng 3 2022

khó quáoho

a: \(A=49+\dfrac{8}{23}-14-\dfrac{8}{23}-5-\dfrac{7}{32}=30-\dfrac{7}{32}=\dfrac{953}{32}\)

b:

Sửa đề: \(B=71\dfrac{38}{45}-\left(43\dfrac{8}{45}-1\dfrac{17}{51}\right)\)

 \(B=71+\dfrac{38}{45}-43-\dfrac{8}{45}+1+\dfrac{17}{51}\)

\(=71-43+1+1\)

=28+2=30

15 tháng 8 2019

\(A=49\frac{8}{23}-\left(5\frac{7}{32}+14\frac{8}{23}\right)\)

\(A=49\frac{8}{23}-5\frac{7}{32}+14\frac{8}{23}\)

\(A= \left(49\frac{8}{23}-14\frac{8}{23}\right)-5\frac{7}{32}\)

\(A=\left[\left(49-14\right)-\left(\frac{8}{23}-\frac{8}{23}\right)\right]-5\frac{7}{32}\)

\(A=\left[35-0\right]-5\frac{7}{32}\)

\(A=35-5\frac{7}{32}\)

\(A=\frac{953}{32}\)

\(B=71\frac{38}{45}-\left(43\frac{38}{45}-1\frac{17}{57}\right)\)

\(B=71\frac{38}{45}-\frac{36377}{855}\)

\(B=\frac{1670}{57}\)

\(C=\left(19\frac{5}{8}:\frac{7}{12}-13\frac{1}{4}:\frac{7}{12}\right):\frac{4}{5}\)

\(C=\left[\left(19\frac{5}{8}-13\frac{1}{4}\right):\frac{7}{12}\right]:\frac{4}{5}\)

\(C=\left[\frac{51}{8}:\frac{7}{12}\right]:\frac{4}{5}\)

\(C=\frac{153}{14}:\frac{4}{5}\)

\(C=\frac{765}{56}\)

\(D=\left[\left(\frac{10}{15}-\frac{2}{3}\right):\frac{1}{7}\right]\cdot0,15-\frac{1}{4}\)

\(D=\left[0:\frac{1}{7}\right]\cdot\frac{3}{20}-\frac{1}{4}\)

\(D=0\cdot\frac{3}{20}-\frac{1}{4}\)

\(D=0-\frac{1}{4}\)

\(D=-\frac{1}{4}\)

\(E=\frac{13}{30}+\frac{28}{45}\cdot2\frac{1}{2}-\left[\left(\frac{1}{2}+\frac{1}{3}\right):\frac{53}{90}\right]:\frac{50}{53}\)

\(E=\frac{13}{30}+\frac{28}{45}\cdot\frac{5}{2}-\left[\frac{5}{6}:\frac{53}{90}\right]:\frac{50}{53}\)

\(E=\frac{13}{30}+\frac{28}{45}\cdot\frac{5}{2}-\frac{75}{53}:\frac{50}{53}\)

\(E=\frac{13}{30}+\frac{14}{9}-\frac{3}{2}\)

\(\)\(E=\frac{22}{45}\)

CHUC BAN HOC TOT >.<