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5^x . 5^1+ 5^x . 5^3=130/5^x . (5^1+5^3)=130/5^x . 130 =130/5^x=130÷130/5^x=1 vậy x=1 tik nha
(x + 1) + (x + 3) + (x + 5) + (x + 7) + (x + 9) = 130
=> x + 1 + x + 3 + x + 5 + x + 7 + x + 9 = 130
=> (x + x + x + x + x) + (1 + 3 + 5 + 7 + 9) = 130
=> 5x + \(\frac{\left(1+9\right)\cdot5}{2}\)= 130
=> 5x + 25 = 130
=> 5x = 105
=> x = 105 : 5 = 21
( x + 1 ) + ( x + 3 ) + ( x + 5 ) + ( x + 7 ) + ( x + 9 ) = 130
x + 1 + x + 3 + x + 5 + x + 7 + x + 9 = 130
5x + 25 = 130
5x = 130 - 125
5x = 105
x = 21
\(\left|x+\frac{2}{3}\right|:5=130\)
\(\Rightarrow\left|x+\frac{2}{3}\right|=650\)
\(\Rightarrow\) \(\left[\begin{array}{nghiempt}x+\frac{2}{3}=650\\x+\frac{2}{3}=-650\end{array}\right.\) \(\Rightarrow\) \(\left[\begin{array}{nghiempt}x=\frac{1948}{3}\\x=\frac{-1952}{3}\end{array}\right.\)
( 99 - 1 ) : 2 + 1 = 50 ( số )
làm bừa thui,ai tích mình mình tích lại
Số số hạng là :
Có số cặp là :
50 : 2 = 25 ( cặp )
Mỗi cặp có giá trị là :
99 - 97 = 2
Tổng dãy trên là :
25 x 2 = 50
Đáp số : 50
\(3^2.x-22=2^2.2^3\Leftrightarrow9x-22=4.8\)
\(\Leftrightarrow9x-22=32\Leftrightarrow9x=32+22\)
\(\Leftrightarrow9x=54\Leftrightarrow x=54:9\)
\(\Leftrightarrow x=6\)
Vậy x = 6
a.1+3+5+7+...+2x+1=225
[(2x+1-1):2+1]x(2x+1+1):2=225
(x+1)x(2x+2):2=225
(x+1)x(x+1)=225
(x+1)2=225
(x+1)2=152
x+1=15
x=14
_______________
b. 130-[5.(9-x)+43]=47
5.(9-x)+43=83
5.(9-x)=40
9-x=8
x=1
_______________
c.16x<324
24x<220
=>x∈{0;1;2;3;4}
a: =>(x+1)^2=225
=>x+1=15
=>x=14
b: =>[5*(9-x)+43]=130-47=83
=>5(9-x)=40
=>9-x=8
=>x=1
c: =>2^4x<2^20
=>4x<20
=>0<x<5
a) 5x = 125
5x = 53
=> x = 3
b) x3 = 64
x3 = 43
=> x = 4
c) ( x - 1 ) 2 = 25
( x - 1 ) 2 = 52
=> x - 1 = 5
=> x = 5 + 1
=> x = 6
d) 5x + 5x+2 = 130
5x . 1 + 5x . 52 = 130
5x . ( 1 + 52 ) = 130
5x . 26 = 130
5x = 130 : 26
5x = 5
=> x = 1
\(1.125+\left(x-5\right)=130\)
\(\Leftrightarrow125+x+5=130\)
\(\Leftrightarrow x=0\)
\(2.127-\left(5-x\right)=120\)
\(\Leftrightarrow127-5+x=120\)
\(\Leftrightarrow122+x=120\)
\(\Leftrightarrow x=-2\)
\(3.25-\left(x-3\right)=12-x\)
\(\Leftrightarrow25-x+3=12-x\)
\(\Leftrightarrow\left(25-x+3\right)-\left(12-x\right)=0\)
\(\Leftrightarrow25-x+3-12+x=0\)
\(\Leftrightarrow-x+x=-16\)
Vì \(x\in Z\) Nên \(x\) không tồn tại.
\(4.\left(-2\right)^3-\left(x-5\right)=-3+x\)
\(\Leftrightarrow-8-x+5-x=-3\)
\(\Leftrightarrow-2x=-3+8-5\)
\(\Leftrightarrow-2x=0\)
\(\Leftrightarrow x=0\)
\(5.\left(-2\right)^2-\left(6-x\right)=13\)
\(\Leftrightarrow4-6+x=13\)
\(\Leftrightarrow-2+x=12\)
\(\Leftrightarrow x=14\)
1, 125 + (x-5)=130
125+x-5=130
x-5=130-125
x-5=5
x=5+5=10
2, 127-(5-x)=120
127+5+x=120
5+x=120-127
5+x=-7
x=-7-5
x=-12
3, 25-(x-3)=12-x
25+x+3=12-x
28+x=12-x
x+x=12-28
2x=16
x=-8
4, \(\left(-2\right)^3-\left(x-5\right)=-3+x\)
\(\left(-2\right)^3\)+x+5=-3+x
\(\left(-2\right)^3\)+5+(-3)=x+x
-8+5-3=2x
-6=2x
x=-3
5, 3.\(\left(-2\right)^2\)-(6-x)=13
3.(-4)+6+x=13
-12+6+x=13
-6+x=13
x=13+6
x=19
a) -11x + 9 = 130
-11x = 121
x = -11
b) -12x = -15.(-4) - 12
-12x = 48
x = -4
c) -5x + 5 = -3 .(-8) = 6 ( đéo hiểu đề kiểu j )
a) \(\left(-11\right)x+9=130\Rightarrow\left(-11\right)x=130-9=121\)
\(\Rightarrow x=\left(-121\right):\left(-11\right)\Leftrightarrow x=-11\)
b) \(\left(-12\right)x=\left(-15\right)\left(-4\right)\left(-12\right)\Rightarrow\left(-12\right)x=\left(-12\right).60\Rightarrow x=60\)
c) P/s : sai đề \(\left(-3\right)\left(-8\right)=24\ne6\)
\(\left(x+5\right)^3+5=130\)
\(\Leftrightarrow\left(x+5\right)^3=125=5^3\)
\(\Leftrightarrow x+5=5\)
\(\Leftrightarrow x=0\)
(x + 5)3 + 5 = 130
(x + 5)3 = 130 - 5
(x + 5)3 = 125
(x + 5)3 = 53
x + 5 = 5
x = 5 - 5
x = 0