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![](https://rs.olm.vn/images/avt/0.png?1311)
trả lời
8x^3-3x^2=0
<=> x^2(8x-3)=0
=> \(\orbr{\begin{cases}x=0\\x=\frac{3}{8}\end{cases}}\)
hok toots
![](https://rs.olm.vn/images/avt/0.png?1311)
a. 12xy2 - 8x2y = 4xy . (3y - 2x)
b. 3x + 3y - x2 - xy = (3x + 3y) - (x2 + xy) = 3 . (x + y) - x . (x + y) = (x + y)(3 - x)
![](https://rs.olm.vn/images/avt/0.png?1311)
2:
=>x^3-1-2x^3-4x^6+4x^6+4x=6
=>-x^3+4x-7=0
=>x=-2,59
4: =>8x-24x^2+2-6x+24x^2-60x-4x+10=-50
=>-62x+12=-50
=>x=1
![](https://rs.olm.vn/images/avt/0.png?1311)
b) ( x+ 2) ( 3x-2) - (3x-1) ( x-5) = 11
3x^2 +6x - 2x -4 - 3x^2 +x + 15x -5 =11
20x = 11 +4+5
20x = 20
x=1
c) 2(2x+ 1) ( 8x-3) + ( 3-4x) ( 8x-7) = 6x + 73
(4x + 2)(8x-3) + 24x - 32x^2 -3 +4x = 6x +73
32x^2 + 16x - 12x + 24x - 32x^2 +4x -6x = 73 +6 +3
26x = 82
x= 41/13
a. \(\left(x+2\right)\left(3x-2\right)-\left(3x-1\right)\left(x-5\right)=11\)
\(\Rightarrow3x^2-2x+6x-4-3x^2+15x+x-5=11\)
\(\Rightarrow20x-9=11\)
\(\Rightarrow x=1\)
Vậy..................
b. \(2\left(2x+1\right)\left(8x-3\right)+\left(3-4x\right)\left(8x-7\right)=6x+73\)
\(\Rightarrow\left(4x+2\right)\left(8x-3\right)+\left(3-4x\right)\left(8x-7\right)=6x+73\)
\(\Rightarrow32x^2-12x+16x-6+24x-21-32x^2+28x-6x=73\)
\(\Rightarrow50x-27=73\)
\(\Rightarrow x=100\)
Vậy..............
![](https://rs.olm.vn/images/avt/0.png?1311)
Câu 1:
Ta có:\(x\left(x^2-y\right)+x\left(y^2-y\right)-x\left(x^2+y^2\right)\)
\(=x\left(x^2-y+y^2-y-x^2-y^2\right)\)
\(=-2xy\)
Tại \(x=\frac{1}{2};y=-100\) PT có dạng:
\(=-2.\frac{1}{2}.\left(-100\right)=100\)
![](https://rs.olm.vn/images/avt/0.png?1311)
g: \(x^2-3x+2=0\)
=>(x-1)(x-2)=0
=>x=1 hoặc x=2
i: \(x^4+x^2+6x-8=0\)
\(\Leftrightarrow x^4-x^3+x^3-x^2+2x^2-2x+8x-8=0\)
\(\Leftrightarrow\left(x-1\right)\left(x^3+x^2+2x+8\right)=0\)
\(\Leftrightarrow\left(x-1\right)\left[\left(x+2\right)\left(x^2-2x+4\right)+x\left(x+2\right)\right]=0\)
\(\Leftrightarrow\left(x-1\right)\left(x+2\right)\left(x^2-x+4\right)=0\)
=>x=1 hoặc x=-2
![](https://rs.olm.vn/images/avt/0.png?1311)
bam may tinh
hoac tính \(\Delta\)
roi ra x=-4+can(21)
x=-4-can(21)
3 ban lay dau ra vay
em ko bít làm em mới lớp 6 thoy à