![](https://rs.olm.vn/images/avt/0.png?1311)
Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
-x + 20 = - (-15) - (8) + 13
-x + 20 = 15 - 8 + 13
-x + 20 = 7 + 13
- x + 20 = 20
x = 20 - 20
x = 0
-(-10) + x = -13 + (-9) + (-6)
10 + x = -13 - 9 - 6
10 + x = -28
x = -28 - 10
x = -38
![](https://rs.olm.vn/images/avt/0.png?1311)
(x+5)+(x-9)=x+2
x+5+x-9=x+2
x+x-x=2-5+9
x=6
Vậy x=6
![](https://rs.olm.vn/images/avt/0.png?1311)
a x b = 2/3 = 6/9
a x (b+5) = 28/9
=> 5a = 22/9
=> a = 22/45
b = 15/11
![](https://rs.olm.vn/images/avt/0.png?1311)
1. -x+20 = -(-15)-8+13
=> -x=15-8+13-20
=> -x=0
=> x=0
2. -(-10)+x=-13+(-9)+(-6)
=> 10+x=-13-9-6
=> x = -13-9-6-10
=> x = -38
3. 8-(-12)+10=-(-14)-x
=> 8+12+10=14-x
=> x = 14-8-12-10
=> x = -16
4. -(+12)+(-x)-(-3)=5-(-7)
=> -12-x+3=5+7
=> -x=5+7+12-3
=> -x=21
=> x=-21
5. 14-x+(-10)=-(-9)+(+15)
=> 14-x-10=9+15
=> -x=9+15-14+10
=> -x=20
=> x=-20
6. 12-(-17)+(-3)=-5+x
=> 12+17-3+5=x
=> x=31
7. x-(-19)-(+32)=14-(+16)
=> x+19-32=14-16
=> x=14-16+32-19
=> x=11
8. x-|-15|-|7|=-(-9)+|-5|
=> x-15-7=9+5
=> x=9+5+7+15
=> x=36
9. 15-x+17=13-(-21)
=> 15-x+17=13+21
=> -x=13+21-15-17
=> -x=2
=> x=-2
10. -|-5|-(-x)+4=3-(-25)
=> -5+x+4=3+25
=> x=3+25-4+5
=> x=29
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\frac{x-1}{-3}\)=\(\frac{2x+5}{5}\)\(\Rightarrow\)5(x-1)=-3(2x+5)
\(\rightarrow\)5x-5=-6x-15
\(\rightarrow\)5x+6x=5-15
\(\rightarrow\)11x=-10\(\Rightarrow\)x=\(\frac{-10}{11}\)
vậy.........................
![](https://rs.olm.vn/images/avt/0.png?1311)
(2016.x+3.y+1).(2016x+2016.x+2016.x+y)=225
=2016+3+1.(x+y).........
...................
tk đi chỉ tiếp
![](https://rs.olm.vn/images/avt/0.png?1311)
x/-30+1,75=-5/9:4/3
=>x/-30+7/4=-5/12
=>x/-30=-13/6
=>x.6=-30.-13
=>x.6=390
=>x=65
vậy x=65.
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\left(x-5\right)^{2016}=x-5\)
\(\Rightarrow\left(x-5\right)^{2016}-\left(x-5\right)=0\)
\(\Rightarrow\left(x-5\right)\left[\left(x-5\right)^{2015}-1\right]=0\)
\(\Rightarrow\orbr{\begin{cases}x-5=0\\\left(x-5\right)^{2015}-1=0\end{cases}}\)
\(\Rightarrow\orbr{\begin{cases}x=5\\\left(x-5\right)^{2015}=1\end{cases}}\)
\(\Rightarrow\orbr{\begin{cases}x=5\\x-5=1\end{cases}}\)
\(\Rightarrow\orbr{\begin{cases}x=5\\x=6\end{cases}}\)
\(Vậy\)\(x\in\left\{5;6\right\}\)
(x - 5)2016 = x - 5
=> (x - 5)2016 - (x - 5) = 0
=> (x - 5).[(x - 5)2015 - 1] = 0
=> \(\orbr{\begin{cases}x-5=0\\\left(x-5\right)^{2015}-1=0\end{cases}\Rightarrow\orbr{\begin{cases}x=5\\\left(x-5\right)^{2015}=1^{2015}\end{cases}\Rightarrow}\orbr{\begin{cases}x=5\\x-5=1\end{cases}\Rightarrow}\orbr{\begin{cases}x=5\\x=6\end{cases}}}\)
Vậy x = 5;x= 6