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a) \(\frac{{37}}{{100}} = 0,37\); \(\frac{{ - 34517}}{{1000}} = - 34,517\)
\(\frac{{ - 254}}{{10}} = - 25,4\); \(\frac{{ - 999}}{{10}} = - 99,9\)
b) \(2 = \frac{2}{1}\); \(2,5 = \frac{{25}}{{10}}\)
\( - 0,007 = \frac{{ - 7}}{{1000}}\); \( - 3,053 = \frac{{ - 3053}}{{1000}}\)
\( - 7,001 = \frac{{ - 7001}}{{1000}}\); \(7,01 = \frac{{701}}{{100}}\).
\(\begin{array}{l}\frac{{ - 3519}}{{100}} = - 35,19;\,\,\,\frac{{ - 778}}{{10}} = - 77,8;\\\,\,\frac{{ - 23}}{{1000}} = - 0,023;\,\,\frac{{88}}{{100}} = 0,88\end{array}\).
a) 2,63=\(2\frac{63}{100}\)
b)\(\frac{2013}{100}\)=\(20\frac{13}{100}\)=20,13
c)\(\frac{-2}{5}=\frac{-14}{35}\)
\(\frac{-3}{7}=\frac{-15}{35}\)
vì\(\frac{-14}{35}>\frac{-15}{35}\Rightarrow\frac{-2}{5}>\frac{-3}{7}\)
\(4\frac{2}{10}m:4,2m\)
\(3\frac{12}{100}km:3,12km\)
\(2\frac{2}{25}kg:2,08kg\)
\(\frac{27}{100}=0,27\) ; \(-\frac{13}{1000}=-0,013\) ; \(\frac{261}{10000}=0,0261\)
\(\frac{6}{5}=1\frac{1}{5}\) ; \(\frac{7}{3}=2\frac{1}{3}\) ; \(\frac{-16}{11}=-1\frac{5}{11}\)
1.
\(\dfrac{19.20}{19+20}=\dfrac{380}{39}=9\dfrac{29}{39}\)
\(\dfrac{\overline{aaa}}{\overline{aa}}=\dfrac{111.a}{11.a}=\dfrac{111}{11}=10\dfrac{1}{11}\)
\(\dfrac{\overline{ababa}}{\overline{aba}}=\dfrac{100.\overline{aba}+\overline{ba}}{\overline{aba}}=\dfrac{100.\overline{aba}}{\overline{aba}}+\dfrac{\overline{ba}}{\overline{aba}}=100\dfrac{\overline{ba}}{\overline{aba}}\)
2.
\(6\dfrac{23}{41}=\dfrac{6.41+23}{41}=\dfrac{269}{41}\)
\(a\dfrac{a}{99}=\dfrac{a.99+a}{99}=\dfrac{100.a}{99}=\dfrac{\overline{a00}}{99}\)
\(1\dfrac{a-b}{a+b}=\dfrac{a+b+a-b}{a+b}=\dfrac{2.a}{a+b}\)
3.
\(\dfrac{69}{1000}=0,069\)
\(8\dfrac{77}{100}=8,77\)
\(\dfrac{34567}{10^4}=\dfrac{34567}{10000}=3,4567\)
\(\dfrac{\overline{abc}}{10^n}=\dfrac{\overline{abc}}{10...0}=\overline{0,0...0abc}\)
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