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24 tháng 4 2023

24 tháng 4 2023

ta rút gọn là xong

 

1 tháng 5 2023

a) Ta có \(A=\dfrac{8}{9}\cdot\dfrac{15}{16}\cdot\dfrac{24}{25}\cdot...\cdot\dfrac{2499}{2500}\)

\(=\dfrac{2\cdot4}{3\cdot3}\cdot\dfrac{3\cdot5}{4\cdot4}\cdot\dfrac{4\cdot6}{5\cdot5}\cdot...\cdot\dfrac{49\cdot51}{50\cdot50}\)

\(=\dfrac{2\cdot4\cdot3\cdot5\cdot4\cdot6\cdot...\cdot49\cdot51}{3\cdot3\cdot4\cdot4\cdot5\cdot5\cdot...\cdot50\cdot50}\)

\(=\dfrac{2\cdot3\cdot4\cdot...\cdot49}{3\cdot4\cdot5\cdot...\cdot50}\cdot\dfrac{4\cdot5\cdot6\cdot...\cdot51}{3\cdot4\cdot5\cdot...\cdot50}\)

\(\dfrac{2}{50}\cdot17=\dfrac{17}{25}\)

b) Vì n nguyên nên 3n - 1 nguyên

Để phân số \(\dfrac{12}{3n-1}\) có giá trị nguyên thì 12 ⋮ ( 3n - 1 ) hay ( 3n - 1 ) ϵ Ư( 12 )

Ư( 12 ) = { \(\pm1;\pm2;\pm3;\pm4;\pm6;\pm12\) }

Lập bảng giá trị 

3n - 1 1 -1 2 -2 3 -3 4 -4 6 -6 12 -12
n \(\dfrac{2}{3}\) 0 1 \(\dfrac{-1}{3}\) \(\dfrac{3}{4}\) \(\dfrac{-2}{3}\) \(\dfrac{5}{3}\) -1 \(\dfrac{7}{3}\) \(\dfrac{-5}{3}\) \(\dfrac{13}{3}\) \(\dfrac{-11}{3}\)

Vì n nguyên nên n ϵ { 0; 1; -1 } 

Vậy n ϵ { 0; 1; -1 } để phân số \(\dfrac{12}{3n-1}\) có giá trị nguyên

9 tháng 5 2021

\(a.\)

\(\dfrac{3}{16}:\dfrac{?}{8}=\dfrac{3}{4}\)

\(\Leftrightarrow\dfrac{3}{16}\cdot\dfrac{8}{?}=\dfrac{3}{4}\)

\(\Leftrightarrow\dfrac{3}{2?}=\dfrac{3}{4}\)

\(\Leftrightarrow?=2\)

\(b.\)

\(\dfrac{1}{25}:-\dfrac{3}{?}=-\dfrac{1}{15}\)

\(\Leftrightarrow\dfrac{1}{25}\cdot\dfrac{-?}{3}=-\dfrac{1}{15}\)

\(\Leftrightarrow\dfrac{-?}{75}=-\dfrac{1}{15}\)

\(\Leftrightarrow?=\dfrac{75}{15}=5\)

\(c.\)

\(\dfrac{?}{12}:-\dfrac{4}{9}=-\dfrac{3}{16}\)

\(\Leftrightarrow\dfrac{?}{12}\cdot\dfrac{-9}{4}=-\dfrac{3}{16}\)

\(\Leftrightarrow\dfrac{-3?}{16}=-\dfrac{3}{16}\)

\(\Leftrightarrow?=1\)

 

Mk gọi ? = x nha

a) \(\dfrac{3}{16}:\dfrac{x}{8}=\dfrac{3}{4}\)  

             \(\dfrac{x}{8}=\dfrac{3}{16}:\dfrac{3}{4}\) 

             \(\dfrac{x}{8}=\dfrac{1}{4}\)

\(x=\dfrac{1.8}{4}=2\) 

b) \(\dfrac{1}{25}:\dfrac{-3}{x}=\dfrac{-1}{15}\) 

             \(\dfrac{-3}{x}=\dfrac{1}{25}:\dfrac{-1}{15}\) 

             \(\dfrac{-3}{x}=\dfrac{-3}{5}\) 

⇒x=5

c) \(\dfrac{x}{12}:\dfrac{-4}{9}=\dfrac{-3}{16}\) 

            \(\dfrac{x}{12}=\dfrac{-3}{16}.\dfrac{-4}{9}\) 

            \(\dfrac{x}{12}=\dfrac{1}{12}\) 

⇒x=1

15 tháng 5 2017

a, -1/3.5/7=-5/21

b,-15/16.8/-25=3/10

c,-21/24.8/-14=1/2

22 tháng 5 2017

\(=\dfrac{1.3}{2^2}.\dfrac{2.4}{3^2}.\dfrac{3.5}{4^2}.\dfrac{4.6}{5^2}...\dfrac{8.10}{9^2}.\dfrac{9.11}{10^2}\)

\(=\dfrac{1.2.3.4...8.9}{2.3.4.5...10}.\dfrac{3.4.5.6...11}{2.3.4.5...10}\)

\(=\dfrac{1}{10}.\dfrac{11}{2}\)

\(=\dfrac{11}{20}\)

Ta có:

\(\dfrac{3}{4}.\dfrac{8}{9}.\dfrac{15}{16}.\dfrac{24}{25}....\dfrac{80}{81}.\dfrac{99}{100}\\ =\dfrac{1.3}{2^2}.\dfrac{2.4}{3^2}.\dfrac{3.5}{4^2}.\dfrac{4.6}{5^2}...\dfrac{8.10}{9^2}.\dfrac{9.11}{10^2}\\ =\dfrac{11}{2.10}=\dfrac{11}{20}\)

2 tháng 4 2017

A=2.4/3^2 . 3.5/4^2 . 4.6/5^2 ............ . 49.51/50^2

A=2/3-51/50

A=17/25.

Chúc bạn hok tốt.

12 tháng 4 2017

Bài này cũng dễ ý mà, vô cùng đơn giản.........

Giải:

Ta có: \(A=\dfrac{8}{9}.\dfrac{15}{16}.\dfrac{24}{25}.....\dfrac{2499}{2500}.\)

\(=\dfrac{2.4}{3^2}.\dfrac{3.5}{4^2}.....\dfrac{49.51}{50^2}.\)

\(=\dfrac{\left(2.3.4.....49\right)\left(4.5.6.....51\right)}{\left(3.4.5.....50\right)\left(3.4.5.....50\right)}.\)

\(=\dfrac{2.51}{3.50}.\)

\(=\dfrac{17}{25}.\)

CHÚC BN HỌC TỐT!!! ^ _ ^

Đừng quên bình luận nếu bài mik sai nhé!!! - _ -

Còn nếu bài mik đúng thì nhớ tick mik để mik lấy SP nha!!! ^ - ^

27 tháng 3 2017

A= 3^2-1/3.3 . 4^2-1/4.4 . 5^2-1/5.5 . ... 50^2-1/50.50 A= (3+1).(3-1).(4+1).(4-1).(5+1).(5-1). ... (50+1).(50-1) / 3.3.4.4.5.5. ... . 50.50 A=4.2.5.3.6.4. ... 51.49 / 3.3.4.4.5.5....50.50 A=(4.5.6. ... .51).(2.3.4. ... 49)/(3.4.5.... .50).(3.4.5.. ... 50) A= 51.2/3.50 A=17/25

11 tháng 4 2017

Ta có:

\(A=\dfrac{8}{9}.\dfrac{15}{16}.\dfrac{24}{25}......\dfrac{2499}{2500}\)

= \(\dfrac{2.4}{3.3}.\dfrac{3.5}{4.4}.\dfrac{4.6}{5.5}......\dfrac{49.51}{50.50}\)

= \(\dfrac{2.4.3.5.4.6......49.51}{3.3.4.4.5.5......50.50}\)

= \(\dfrac{\left(2.3.4....49\right)\left(4.5.6....51\right)}{\left(3.4.5....50\right)\left(3.4.5....50\right)}\)

= \(\dfrac{2}{50}.\dfrac{51}{3}\) = \(\dfrac{17}{25}\)

4 tháng 7 2017

\(A=\dfrac{3}{2^2}.\dfrac{8}{3^2}.\dfrac{15}{4^2}.....\dfrac{899}{30^2}\)

\(A=\dfrac{1.3}{2.2}.\dfrac{2.4}{3.3}.\dfrac{3.5}{4.4}.....\dfrac{29.31}{30.30}\)

\(A=\dfrac{1.3.2.4.3.5.....29.31}{2.2.3.3.4.4.....30.30}\)

\(A=\dfrac{1.2.3.....29}{2.3.4....30}.\dfrac{3.4.5.....31}{2.3.4.....30}\)

\(A=\dfrac{1}{30}.\dfrac{31}{2}=\dfrac{31}{60}\)

\(B=\dfrac{8}{9}.\dfrac{15}{16}.\dfrac{24}{25}.....\dfrac{2499}{2500}\)

\(B=\dfrac{2.4}{3.3}.\dfrac{3.5}{4.4}.\dfrac{4.6}{5.5}.....\dfrac{49.51}{50.50}\)

\(B=\dfrac{2.4.3.5.4.6.....49.51}{3.3.4.4.5.5....50.50}\)

\(B=\dfrac{2.3.4......49}{3.4.5....50}.\dfrac{4.5.6.....51}{3.4.5....50}\)

\(B=\dfrac{2}{50}.\dfrac{51}{3}=\dfrac{17}{25}\)

4 tháng 7 2017

Giải:

\(A=\dfrac{3}{2^2}.\dfrac{8}{3^2}.\dfrac{15}{4^2}.....\dfrac{899}{30^2}.\)

\(A=\dfrac{1.3}{2^2}.\dfrac{2.4}{3^2}.\dfrac{3.5}{4^2}.....\dfrac{29.31}{30^2}.\)

\(A=\dfrac{1.2.3.....29}{2.3.4.....30}.\dfrac{2.3.4.....31}{2.3.4.....30}.\)

\(A=\dfrac{1}{30}.31=\dfrac{30}{31}.\)

Vậy \(A=\dfrac{30}{31}.\)

14 tháng 5 2021

`16/803+38+(-16/803)`
`=16/803-16/803+38`
`=0+38=38`

14 tháng 5 2021

`100/91+310-9/91`
`=100/91-9/91+310`
`=1+310=311`