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Gợi ý : Phân tích hết ra thành tích các thừa số nguyên tố rồi đặt cái chung ra ngoài
-> rút gọn
-> kết quả
P/S : bài này cx ko dài lắm nhưg lười ^^
c: \(C=\dfrac{\left(\dfrac{2}{5}\cdot5\right)^7+\dfrac{9^3}{4^3}:\dfrac{3^3}{16^3}}{2^7\cdot5^2+2^9}=\dfrac{1+1728}{3712}=\dfrac{1729}{3712}\)
\(D=\dfrac{2^{12}\cdot3^5-2^{12}\cdot3^4}{2^{12}\cdot3^6+2^{12}\cdot3^5}=\dfrac{3^5-3^4}{3^6+3^5}=\dfrac{3^4\left(3-1\right)}{3^5\left(3+1\right)}=\dfrac{2}{3\cdot4}=\dfrac{2}{12}=\dfrac{1}{6}\)
\(E=\dfrac{5^{10}\cdot7^3-5^{10}\cdot7^4}{5^9\cdot7^3+5^9\cdot7^3\cdot2^3}=\dfrac{5^{10}\cdot7^3\cdot\left(-6\right)}{5^9\cdot7^3\cdot9}=5\cdot\dfrac{-2}{3}=\dfrac{-10}{3}\)
\(B=\frac{2^{12}.3^5-4^6.9^2}{\left(2^2.3\right)^6+8^4.3^5}-\frac{5^{10}.7^3-25^5.49^2}{\left(125.7\right)^3+5^9.14^3}\)
\(=\frac{2^{12}.3^5-2^{12}.3^6}{2^{12}.3^6+2^{12}.3^5}-\frac{5^{10}.7^3-5^{10}.7^4}{5^9.7^3+5^9.2^3.7^3}\)
\(=\frac{2^{12}.3^5.\left(1-3\right)}{2^{12}.3^6.\left(3+1\right)}-\frac{5^9.7^3.\left(1-7\right)}{5^9.7^3\left(1+2^3.1\right)}\)
\(=\frac{-1}{2}-\frac{-2}{3}=\frac{-7}{6}\)
3) C thiếu đề
4) \(D=\frac{1}{9}-\left|\frac{-5}{23}\right|-\left(\frac{-5}{23}+\frac{1}{9}+\frac{25}{7}\right)+\frac{50}{4}-\frac{7}{30}\)
\(D=\frac{1}{9}-\frac{5}{23}+\frac{5}{23}-\frac{1}{9}-\frac{25}{7}+\frac{50}{4}-\frac{7}{30}\)
\(D=\frac{1}{9}-\frac{1}{9}-\frac{5}{23}+\frac{5}{23}+\frac{-25}{7}+\frac{50}{4}-\frac{7}{30}\)
\(D=0+0+\frac{125}{14}-\frac{7}{30}\)
\(D=\frac{913}{105}\)
a) \(\left(-\frac{4}{7}\right)^{25}:\left(-\frac{4}{7}\right)^{23}=\left(-\frac{4}{7}\right)^{25-23}=\left(-\frac{4}{7}\right)^2=\frac{16}{49}\)
b) \(\frac{15}{60}+\frac{12}{19}+\frac{2}{9}+\frac{10}{8}+\frac{-31}{19}\)
\(=\frac{1}{4}+\frac{2}{9}+\frac{5}{4}+\left(\frac{12}{19}+\frac{-31}{19}\right)\)
\(=\frac{3}{2}+\frac{2}{9}-1=\frac{1}{2}+\frac{2}{9}=\frac{13}{18}\)
a, \((\frac{-4}{7})^{25}:\left(\frac{-4}{7}\right)^{23}=\left(-\frac{4}{7}\right)^2=\frac{16}{49}\)
b,\(\frac{15}{60}+\frac{12}{19}+\frac{2}{9}+\frac{10}{8}+\frac{-31}{19}=\frac{1}{4}+\frac{2}{9}+\frac{5}{4}-1=\frac{6}{4}-\frac{7}{9}=\frac{3}{2}-\frac{7}{9}=\frac{13}{18}\)
c,\(\frac{5^{10}.7^3-25^5.49^2}{\left(125.7\right)^3.5^9.7^3.8}=\frac{5^{10}.7^3-5^{10}.7^4}{5^9.7^3.5^9.7^3.8}=-\frac{6.5^{10}.7^3}{5^{18}.7^6.8}=-\frac{3}{5^8.7^3.4}\)