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NM
4
29 tháng 9 2018
=(5016+912). 37 : 13 : 74
=5928.37 : 13 : 74
=219336 : 13 : 74
=16872:74
=2410
29 tháng 9 2018
(456.11+912).37:13:74
= (456.11+912):13:(74:37)
= (456.11+456.2):13:2
= 456.(11+2):13:2
= 456.13:13:2
= (456:2).(13:13)
= 228.1
= 228
NM
2
26 tháng 12 2016
1+2-3-4+5+6-7-8+9+................+33
=1+(2-3-4+5)+(6-7-8+9)+............+(30-31-32+33)
=1+0+0+..............+0
=1
NN
1 tháng 8 2020
a) \(\frac{1}{2.3}+\frac{1}{3.4}+\frac{1}{4.5}+........+\frac{1}{99.100}\)
\(=\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-\frac{1}{5}+.........+\frac{1}{99}-\frac{1}{100}\)
\(=\frac{1}{2}-\frac{1}{100}=\frac{49}{100}\)
b) \(\frac{2}{3.5}+\frac{2}{5.7}+\frac{2}{7.9}+..........+\frac{2}{73.75}\)
\(=\frac{1}{3}-\frac{1}{5}+\frac{1}{5}-\frac{1}{7}+\frac{1}{7}-\frac{1}{9}+.......+\frac{1}{73}-\frac{1}{75}\)
\(=\frac{1}{3}-\frac{1}{75}=\frac{8}{25}\)
c) \(\frac{4}{4.6}+\frac{4}{6.8}+\frac{4}{8.10}+..........+\frac{4}{64.66}\)
\(=2.\left(\frac{2}{4.6}+\frac{2}{6.8}+\frac{2}{8.10}+..........+\frac{2}{64.66}\right)\)
\(=2.\left(\frac{1}{4}-\frac{1}{6}+\frac{1}{6}-\frac{1}{8}+\frac{1}{8}-\frac{1}{10}+.....+\frac{1}{64}-\frac{1}{66}\right)\)
\(=2.\left(\frac{1}{4}-\frac{1}{66}\right)=2.\frac{31}{132}=\frac{31}{66}\)
NN
1 tháng 8 2020
d) \(\frac{9}{5.8}+\frac{9}{8.11}+\frac{9}{11.14}+........+\frac{9}{497.500}\)
\(=3.\left(\frac{3}{5.8}+\frac{3}{8.11}+\frac{3}{11.14}+..........+\frac{3}{497.500}\right)\)
\(=3.\left(\frac{1}{5}-\frac{1}{8}+\frac{1}{8}-\frac{1}{11}+\frac{1}{11}-\frac{1}{14}+......+\frac{1}{497}-\frac{1}{500}\right)\)
\(=3.\left(\frac{1}{5}-\frac{1}{500}\right)=3.\frac{99}{500}=\frac{297}{500}\)
e) \(\frac{1}{5.7}+\frac{1}{7.9}+\frac{1}{9.11}+......+\frac{1}{93.95}\)
\(=\frac{1}{2}.\left(\frac{2}{5.7}+\frac{2}{7.9}+\frac{2}{9.11}+........+\frac{2}{93.95}\right)\)
\(=\frac{1}{2}.\left(\frac{1}{5}-\frac{1}{7}+\frac{1}{7}-\frac{1}{9}+\frac{1}{9}-\frac{1}{11}+........+\frac{1}{93}-\frac{1}{95}\right)\)
\(=\frac{1}{2}.\left(\frac{1}{5}-\frac{1}{95}\right)=\frac{1}{2}.\frac{18}{95}=\frac{9}{95}\)
g) \(\frac{1}{2.5}+\frac{1}{5.8}+\frac{1}{8.11}+..........+\frac{1}{200.203}\)
\(=\frac{1}{3}.\left(\frac{3}{2.5}+\frac{3}{5.8}+\frac{3}{8.11}+........+\frac{3}{200.203}\right)\)
\(=\frac{1}{3}.\left(\frac{1}{2}-\frac{1}{5}+\frac{1}{5}-\frac{1}{8}+\frac{1}{8}-\frac{1}{11}+......+\frac{1}{200}-\frac{1}{203}\right)\)
\(=\frac{1}{3}.\left(\frac{1}{2}-\frac{1}{203}\right)=\frac{1}{3}.\frac{201}{406}=\frac{67}{406}\)
BQ
1
9 tháng 8 2018
\(\frac{21}{11}\times\frac{22}{17}\times\frac{68}{63}\)
=\(\frac{21}{1}\times\frac{2}{17}\times\frac{68}{63}\)
= 21 x \(\frac{8}{63}\)
=\(\frac{8}{3}\)
75% - ( 1,25 - \(\dfrac{11}{4}\)) : \(\dfrac{9}{2}\)
= \(\dfrac{75}{100}\) - ( \(\dfrac{125}{100}\)- \(\dfrac{11}{4}\)) : \(\dfrac{9}{2}\)
= \(\dfrac{3}{4}\) - (\(\dfrac{5}{4}\)- \(\dfrac{11}{4}\)) x \(\dfrac{2}{9}\)
= \(\dfrac{3}{4}\) + \(\dfrac{6}{4}\) x \(\dfrac{2}{9}\)
= \(\dfrac{3}{4}\)+ \(\dfrac{1}{3}\)
= \(\dfrac{13}{12}\)
`75% - (1,25 - 11/4) : 9/2`
`=75/100 - (5/4 - 11/4):9/2`
`=3/4 - (5/4 - 11/4):9/2`
`=3/4 - (-3/2): 9/2`
`=3/4 + 3/2 : 9/2`
`=3/4 + 3/2 xx 2/9`
`=3/4 + 1/3`
`=9/12 + 4/12`
`=13/12`