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49 x 19 + 48 x 115 + 134 x 52
= 931 + 5520 + 6968
= 13419
Đặt \(A=\frac{3}{5.11}+\frac{5}{11.21}+\frac{7}{21.35}+\frac{9}{35.53}\)
\(2A=\frac{6}{5.11}+\frac{10}{11.21}+\frac{14}{21.35}+\frac{18}{35.53}\)
\(2A=\frac{1}{5}-\frac{1}{11}+\frac{1}{11}-\frac{1}{21}+\frac{1}{21}-\frac{1}{35}+\frac{1}{35}-\frac{1}{53}\)
\(2A=\frac{1}{5}-\frac{1}{53}\)
\(2A=\frac{48}{265}\)
\(A=\frac{48}{265}:2\)
\(A=\frac{24}{265}\)
Vì \(\frac{24}{265}< 1\)nên \(A< 1\)(Điều phải chứng tỏ)
Ủng hộ mk nha !!! ^_^
\(=5.22\left(3134+275\cdot2+1.079\cdot4\right)\)
\(=5.22\cdot3688.316=19253.00952\)
\(1\dfrac{13}{15}.0,75-\left(\dfrac{11}{20}+25\%\right):\dfrac{3}{7}\)
\(\Leftrightarrow\) \(\left\{{}\begin{matrix}=\dfrac{28}{15}.\dfrac{3}{4}-\left(\dfrac{11}{20}+\dfrac{1}{4}\right):\dfrac{7}{3}\\=\dfrac{7}{5}-\dfrac{4}{5}.\dfrac{3}{7}\\=\dfrac{7}{5}-\dfrac{12}{35}\\=\dfrac{37}{35}\end{matrix}\right.\)\(\Rightarrow\) \(kết\) \(quả\) \(=\dfrac{37}{35}\)
\(\Rightarrow C=\left(-\dfrac{3}{4}\right)\cdot\left(-\dfrac{8}{9}\right)\cdot\left(-\dfrac{15}{16}\right)\cdot\cdot\cdot\cdot\left(-\dfrac{399}{400}\right)\)
\(=-\left(\dfrac{3}{4}\cdot\dfrac{8}{9}\cdot\dfrac{15}{16}\cdot\cdot\cdot\cdot\dfrac{399}{400}\right)\)
\(=-\left(\dfrac{1\cdot3}{2\cdot2}\cdot\dfrac{2\cdot4}{3\cdot3}\cdot\dfrac{3\cdot5}{4\cdot4}\cdot\cdot\cdot\cdot\dfrac{19\cdot21}{20\cdot20}\right)\)
\(=-\left(\dfrac{1\cdot2\cdot3\cdot4\cdot...\cdot19}{2\cdot3\cdot4\cdot...\cdot20}\cdot\dfrac{3\cdot4\cdot5\cdot...\cdot21}{2\cdot3\cdot4\cdot...\cdot20}\right)\)
\(=-\left(\dfrac{1}{20}\cdot\dfrac{21}{2}\right)=-\dfrac{21}{40}\)
7.24.28-7.7.19-7.3.35
7.9(24.28-7.19-3.35)
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