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Ta có:\(77^2+23^2+77.46\)
\(=77^2+2.23.77+23^2\)
\(=\left(77+23\right)^2\)
\(=100^2=10000\)
=77*77+23*23+77*46
=77*(77+46)+23*23
=77*123+23*23
=9471+529
=1000
![](https://rs.olm.vn/images/avt/0.png?1311)
772 + 232 + 77.46 = 772 + 232 + 2.77.23
= (77 + 23)2 = 1002 = 10000
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
1012
= (100 + 1)²
= 100² + 2.100.1 + 1²
= 10000 + 200 + 1
= 10201
a. 1012 = 10201
b. 97 x 103 = 9991
c. 772 + 232 + 77 x 46
= 5929 + 529 + 77 x 46
= 5929 + 529 + 3542
= 6458 + 3542
= 10000
d. 1052 - 5
= 11025 - 5
= 11020
![](https://rs.olm.vn/images/avt/0.png?1311)
b1 A=10000 B=23386
b2 a,x=5
b,x=4 x=2
có lẽ bn nên tự lm thì hơn
a: \(x^2-10x=-25\)
\(\Leftrightarrow x-5=0\)
hay x=5
b: \(x^2-6x+8=0\)
\(\Leftrightarrow\left(x-2\right)\left(x-4\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}x=2\\x=4\end{matrix}\right.\)
![](https://rs.olm.vn/images/avt/0.png?1311)
a) 1012
= (100 + 1)2
= 1002 + 2.100 + 1
= 10000 + 200 + 1
= 10201
b) 97.103
= (100 - 3)(100 + 3)
= 1002 - 32
= 10000 - 9
= 9991
c) 772 + 232 + 77.46
= 772 + 2.77.23 + 232
= (77 + 23)2
= 1002
= 10000
d) 1052 - 52
= (105 - 5)(105 + 5)
= 100.110
= 11000
![](https://rs.olm.vn/images/avt/0.png?1311)
\(77^2+23+77.46\)
\(=77.77+23+77.46\)
\(=77.\left(77+46\right)+23\)
\(=77.123+23\)
\(=9471+23=9494\)
\(77^2+23+77.46\)
\(=77.77+23+77.46\)
\(=77.\left(77+46\right)+23\)
\(=77.123+23\)
\(=9471+23\)
\(=9494\)
![](https://rs.olm.vn/images/avt/0.png?1311)
a.\(^{101^2}\)= 10201
b.97 x 103 = 9991
c.\(^{77^2}+^{23^2}+77\times46\)=10000
d.\(^{105^5}-^{5^2}\)= 12762815600
77^2-23^2
=5929-529
=5400
\(77^2-23^2\)
\(=5929-529\)
\(=5400\)