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3 tháng 3 2023
\(-\dfrac{2}{5}.\dfrac{4}{7}+\dfrac{-3}{5}.\dfrac{2}{7}+\dfrac{-3}{5}\)
= \(\dfrac{-8}{35}+\dfrac{-6}{35}+\dfrac{-3}{5}\)
=\(\dfrac{-8-6-21}{35}\)
=\(\dfrac{-35}{35}\)
=-1
3 tháng 3 2023
`(-2)/5.4/7+(-3)/5.2/7+(-3)/5`
`=(-8)/3 +(-6)/35+(-3)/5`
`=(-8)-6-21/35`
`=(-35)/35`
`=(-1)`
`@Nae`
VK
2
31 tháng 1 2023
\(#N\)
\(-\dfrac{11}{7}+\dfrac{13}{-2}+-\dfrac{6}{17}=-\dfrac{113}{14}+-\dfrac{6}{17}=-\dfrac{2005}{238}\)
\(\dfrac{13}{-8}+-\dfrac{7}{20}+\dfrac{3}{-8}=\left(-\dfrac{13}{8}+-\dfrac{3}{8}\right)+-\dfrac{7}{20}=-2+-\dfrac{7}{20}=-\dfrac{47}{20}\)
\(-\dfrac{4}{7}+\dfrac{11}{5}+\dfrac{1}{5}+-\dfrac{7}{3}=-\dfrac{4}{7}+\left(\dfrac{11}{5}+\dfrac{1}{5}\right)+-\dfrac{7}{3}=-\dfrac{4}{7}+\dfrac{12}{5}+-\dfrac{7}{3}=-\dfrac{53}{105}\)
H
2
BA
7 tháng 5 2019
\(a,-\frac{4}{7}+\left(-\frac{2}{3}+\frac{3}{7}\right)=-\frac{4}{7}-\frac{2}{3}+\frac{3}{7}=-\frac{4}{7}+\frac{3}{7}-\frac{2}{3}=-\frac{1}{7}-\frac{2}{3}=-\frac{17}{21}\)
\(b,-\frac{3}{10}\cdot\frac{5}{12}+-\frac{3}{10}\cdot\frac{7}{12}+5\cdot\frac{3}{10}=\frac{3}{10}\cdot-\frac{5}{12}+\frac{3}{10}\cdot-\frac{7}{12}+5\cdot\frac{3}{10}=\frac{3}{10}\cdot\left(-\frac{5}{12}-\frac{7}{12}+5\right)\)
\(=\frac{3}{10}\cdot4=\frac{6}{5}\)
ti ck nha
đúng đó
xin đó
#####
MH
8 tháng 5 2022
\(=\dfrac{-3}{5}:\dfrac{7}{5}-\dfrac{3}{5}:\dfrac{7}{5}+2\dfrac{3}{5}\)
\(=-\dfrac{6}{5}\times\dfrac{5}{7}+\dfrac{13}{5}=\dfrac{61}{35}\)
VM
4
Y
13 tháng 6 2023
\(\left(\dfrac{1}{3}-\dfrac{3}{10}\right):\dfrac{3}{5}+\left(\dfrac{2}{3}-\dfrac{7}{10}\right):\dfrac{3}{5}\)
\(=\left(\dfrac{1.10}{3.10}-\dfrac{3.3}{10.3}\right).\dfrac{5}{3}+\left(\dfrac{2.10}{3.10}-\dfrac{7.3}{10.3}\right).\dfrac{5}{3}\)
\(=\left(\dfrac{10}{30}-\dfrac{9}{30}\right).\dfrac{5}{3}+\left(\dfrac{20}{30}-\dfrac{21}{30}\right).\dfrac{5}{3}\)
\(=\dfrac{1}{30}.\dfrac{5}{3}-\dfrac{1}{30}.\dfrac{5}{3}\)
\(=\dfrac{5}{3}.\left(\dfrac{1}{30}-\dfrac{1}{30}\right)\)
\(=\dfrac{5}{3}.0\)
\(=0\)
QA
2
7 tháng 5 2019
\(\frac{-4}{7}+\left(\frac{-2}{3}+\frac{4}{7}\right)\)
\(=\frac{-4}{7}+\frac{-2}{3}+\frac{4}{7}\)
\(=\left(\frac{-4}{7}+\frac{4}{7}\right)+\frac{-2}{3}\)
\(=0+\frac{-2}{3}=\frac{-2}{3}\)
~ Hok tốt ~
7 tháng 5 2019
\(\frac{-3}{10}.\frac{5}{12}+\frac{-3}{10}.\frac{7}{12}+5\frac{3}{10}\)
\(=\frac{-3}{10}.\frac{5}{12}+\frac{-3}{10}.\frac{7}{12}+\frac{53}{10}\)
\(=\frac{-3}{10}.\left(\frac{5}{12}+\frac{7}{12}\right)+\frac{53}{10}\)
\(=\frac{-3}{10}.1+\frac{53}{10}\)
\(=\frac{-3}{10}+\frac{53}{10}=\frac{50}{10}=5\)
~ Hok tốt ~
TY
5
15 tháng 2 2022
\(\dfrac{2}{7}-\dfrac{3}{11}+\dfrac{5}{7}-\dfrac{8}{11}\\ =\left(\dfrac{2}{7}+\dfrac{5}{7}\right)-\left(\dfrac{3}{11}+\dfrac{8}{11}\right)\\ =\dfrac{7}{7}-\dfrac{11}{11}\\ =1-1\\ =0\)
16 tháng 4 2022
a: =(-20/23-3/23)+(2/3+2/5+7/15)
=-1+10/15+6/15+7/15
=23/15-1=8/15
b: \(=\dfrac{7}{5}\cdot\dfrac{29}{4}-\dfrac{7}{5}\cdot\dfrac{9}{4}+\dfrac{41}{13}=\dfrac{7}{5}\cdot5+\dfrac{41}{13}=7+\dfrac{41}{13}=\dfrac{132}{13}\)
c: =3,07+7,005-23,005+5,23
=8,3-16
=-7,7
\(\frac{-7^5\times3^3}{7^2\times\left(-3\right)^3}\)\(=\frac{7^5\times3^3}{7^2\times3^3}\)\(=\frac{7^5}{7^2}\)\(=7^3=343\)
-7^5×3^3/7^2×3^3
= -7^3×7^2×3^3/7^2×3^3
=)-7^3