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\(a,\dfrac{6}{11}+6+\dfrac{5}{7}=\dfrac{42+462+55}{77}=\dfrac{559}{77}\)
\(b,\dfrac{9}{8}\times\dfrac{3}{12}:\dfrac{5}{9}=\dfrac{9}{8}\times\dfrac{3}{12}\times\dfrac{9}{5}=\dfrac{243}{480}=\dfrac{81}{160}\)
\(c,\dfrac{8}{7}:4+2=\dfrac{8}{7}\times\dfrac{1}{4}+2=\dfrac{8}{28}+2=\dfrac{2}{7}+2=\dfrac{16}{7}\)
\(d,\dfrac{3}{5}+4:\dfrac{6}{4}=\dfrac{3}{5}+4\times\dfrac{4}{6}=\dfrac{3}{5}+\dfrac{8}{3}=\dfrac{49}{15}\)
Bài 1:
a: x+1/2=5/6
nên x=5/6-1/2=1/3
b: x+1/4=3/4
nên x=3/4-1/4=2/4=1/2
c: x+3/10=1/2
nên x=1/2-3/10=5/10-3/10=1/5
d: x+1/4=3/8
nên x=3/8-1/4=3/8-2/8=1/8
1. a) \(\frac{6}{11}+\frac{7}{5}=\frac{30}{55}+\frac{77}{55}=\frac{30+77}{55}=\frac{107}{55}\)
b) \(\frac{9}{5}-\frac{6}{7}=\frac{63}{35}-\frac{30}{35}=\frac{63-30}{35}=\frac{33}{35}\)
c) \(\frac{11}{2}-3=\frac{11}{2}-\frac{3}{1}=\frac{11}{2}-\frac{6}{2}=\frac{11-6}{2}=\frac{5}{2}\)
d) \(15+\frac{1}{3}=\frac{15}{1}+\frac{1}{3}=\frac{45}{3}+\frac{1}{3}=\frac{45+1}{3}=\frac{46}{3}\)
2. a)\(\frac{3}{7}\cdot\frac{7}{2}=\frac{21}{14}\)
b) \(6\cdot\frac{7}{9}=\frac{42}{9}\)
c) \(\frac{8}{15}\cdot5=\frac{40}{15}\)
d) \(\frac{6}{13}\cdot\frac{26}{2}=\frac{156}{26}\)
Dấu chấm mấy bài trên thay thế cho dấu nhân nhá..
\(\dfrac{3}{7}\times\dfrac{7}{5}:\dfrac{3}{10}+\dfrac{1}{6}\)
\(=\dfrac{3}{5}:\dfrac{3}{10}+\dfrac{1}{6}\)
\(=2+\dfrac{1}{6}\)
\(=\dfrac{12}{6}+\dfrac{1}{6}=\dfrac{13}{6}\)
\(\Leftrightarrow C\)
`3/7 xx 7/5 : 3/10 + 1/6`
` = 3/7 xx 7/5 xx 10/3 + 1/6`
` = ( 3xx7xx10)/(7xx5xx3) + 1/6`
`=210/105 + 1/6`
`= 2 + 1/6`
`= 12/6 + 1/6`
`=13/6`
`=> C`