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Ta có: \(\frac{1}{2}.x+\frac{3}{5}.\left(x-2\right)=3\)
\(\Rightarrow\frac{1}{2}x+\frac{3}{5}x-\frac{6}{5}=3\)
\(\Rightarrow\frac{11}{10}x-\frac{6}{5}=3\)
\(\Rightarrow\frac{11}{10}x=3+\frac{6}{5}=\frac{21}{5}\)
\(\Rightarrow x=\frac{21}{5}:\frac{11}{10}=\frac{42}{11}\)
Vậy \(x=\frac{42}{11}\)
Ủng hộ tớ nha?
![](https://rs.olm.vn/images/avt/0.png?1311)
\(x.3\frac{1}{4}+\left(\frac{-7}{6}\right)x-1\frac{2}{3}=\frac{5}{12}\)
\(x.\frac{13}{4}+\left(\frac{-7}{6}\right)x-\frac{5}{3}=\frac{5}{12}\)
\(x\left[\frac{13}{4}+\left(\frac{-7}{6}\right)\right]-\frac{5}{3}=\frac{5}{12}\)
\(x\frac{25}{12}-\frac{5}{3}=\frac{5}{12}\)
\(x\frac{25}{12}=\frac{5}{12}+\frac{5}{3}\)
\(x\frac{25}{12}=\frac{25}{12}\)
\(x=\frac{25}{12}:\frac{25}{12}\)
\(x=1\)
![](https://rs.olm.vn/images/avt/0.png?1311)
1)
\(\frac{3}{4}.x+\frac{x}{5}=\frac{1}{6}\)
\(x.\left(\frac{3}{4}+\frac{1}{5}\right)=\frac{1}{6}\)
\(x.\frac{19}{20}=\frac{1}{6}\)
\(x=\frac{1}{6}:\frac{19}{20}\)
\(x=\frac{10}{57}\)
2)
\(x+3\frac{1}{2}+x=24\frac{1}{4}\)
\(2x+3\frac{1}{2}=24\frac{1}{4}\)
\(2x=24\frac{1}{4}-3\frac{1}{2}\)
\(2x=\frac{83}{4}\)
\(x=\frac{83}{4}:2\)
\(x=\frac{83}{8}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
a.
\(\frac{4}{7}x-\frac{2}{3}=\frac{1}{5}\)
\(\frac{4}{7}x=\frac{1}{5}+\frac{2}{3}\)
\(\frac{4}{7}x=\frac{3+10}{15}\)
\(\frac{4}{7}x=\frac{13}{15}\)
\(x=\frac{13}{15}\div\frac{4}{7}\)
\(x=\frac{13}{15}\times\frac{7}{4}\)
\(x=\frac{91}{60}\)
b.
\(\frac{2}{9}+\frac{7}{8}x=\frac{1}{3}\)
\(\frac{7}{8}x=\frac{1}{3}-\frac{2}{9}\)
\(\frac{7}{8}x=\frac{3-2}{9}\)
\(\frac{7}{8}x=\frac{1}{9}\)
\(x=\frac{1}{9}\div\frac{7}{8}\)
\(x=\frac{1}{9}\times\frac{8}{7}\)
\(x=\frac{8}{63}\)
Chúc bạn học tốt
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\frac{1}{2}.x-\frac{3}{5}=\frac{4}{3}\)
=>\(\frac{1}{2}x=\frac{4}{3}+\frac{3}{5}=\frac{29}{15}\)
=> x= \(\frac{29}{15}:\frac{1}{2}=\frac{29}{15}.\frac{2}{1}=\frac{58}{15}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
a) X-4,2=58,4-24,9
X-4,2= 33,5
X= 33,5+4,2
X=37,7
b) \(\frac{4}{5}-X=\frac{1}{5}+\frac{2}{7}\)
\(\frac{4}{5}-X=\frac{17}{35}\)
\(X=\frac{4}{5}-\frac{17}{35}\)
\(X=\frac{5}{7}\)
c)\(X-140:35=270\)
\(X-4=270\)
X=274
d) 3.X + 2.X = 25
X.(3+2) = 25
X = 25:(3+2)
X=5
a) b) \(\frac{4}{5}-x=\frac{1}{5}+\frac{2}{7}\)
x – 4,2 = 58,4 – 24,9 \(\frac{4}{5}-x=\frac{17}{35}\)
x – 4,2 = 33,5 \(x=\frac{4}{5}-\frac{17}{35}\)
x = 33,5 + 4,2 \(x=\frac{11}{35}\)
x = 37,7
c) d) \(3\times x+2\times x=25\)
x – 140 : 35 = 270 \(x\times\left(3+2\right)=25\)
x - 4 = 270 \(x\times5=25\)
x = 270 + 4 \(x=25\div5\)
x = 274 \(x=5\)