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130-[5.(9-x)+43]=47
5.(9-x)+43=130-47
5.(9-x)+43=83
5.(9-x)=83-43
5.(9-x)=40
9-x=40:5
9-x=8
x=9-8
x=1
\(130-\left[5\times\left(9-x\right)+43\right]=47\)
\(\Rightarrow\left[5\times\left(9-x\right)+43\right]=130-47\)
\(\Rightarrow\left[5\times\left(9-x\right)\right]=83\)
\(\Rightarrow\left(9-x\right)=83\div5\)
\(\Rightarrow\left(9-x\right)=\frac{83}{5}\)
\(\Rightarrow x=9-\frac{83}{5}\)
\(\Rightarrow x=-\frac{38}{5}\)
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a) Ta có: \(18-x=58-\left(-30\right)\)
\(\Leftrightarrow18-x=88\)
\(\Leftrightarrow x=18-88=-70\)
Vậy: x=-70
b) Ta có: \(x-27=\left(-43\right)-9\)
\(\Leftrightarrow x-27=-43-9\)
\(\Leftrightarrow x-27=-52\)
\(\Leftrightarrow x=-25\)
Vậy: x=-25
c) Ta có: \(169-\left(x+4\right)=69\)
\(\Leftrightarrow x+4=169-69\)
\(\Leftrightarrow x+4=100\)
\(\Leftrightarrow x=96\)
Vậy: x=96
d) Ta có: \(\left(5x+3\right)-\left(-24+4\right)=33\)
\(\Leftrightarrow5x+3+24-4-33=0\)
\(\Leftrightarrow5x-10=0\)
\(\Leftrightarrow5x=10\)
\(\Leftrightarrow x=2\)
Vậy: x=2
e) Ta có: \(225-\frac{\left(5x+10\right)}{25}+5=-\left(-20\right)\)
\(\Leftrightarrow225-\frac{5x+10}{25}+5-20=0\)
⇔\(-\frac{5x+10}{25}+210=0\)
\(\Leftrightarrow-\frac{5x+10}{25}=-210\)
⇔\(\frac{5x+10}{25}=210\)
\(\Leftrightarrow5x+10=210\cdot25=5250\)
\(\Leftrightarrow5x=5250-10=5240\)
\(\Leftrightarrow x=1048\)
Vậy: x=1048
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a , 130 - [ 5 . ( 9 - x ) + 43 ] = 47
[ 5 . ( 9 - x ) + 43 ] = 130 - 47
[ 5 . ( 9 - x ) + 43 ] = 83
5 . ( 9 - x ) = 83 - 43
5 . ( 9 - x ) = 40
9 - x = 40 : 5
9 - x = 8
x = 9 - 8
x = 1
b , [ 2 .( 70 - x ) + 23 . 32 ] : 2 = 46
[ 2 . ( 70 - x ) + 8 . 9 ] : 2 = 46
[ 2 . ( 70 - x ) + 72 ] : 2 = 46
[ 2 . ( 70 - x ) + 72 ] = 92
( 70 - x ) + 72 = 92 : 2
( 70- x ) + 72 = 46
( 70 - x ) = 46 - 72
70 - x = - 26
x = 70 - ( - 26 )
x = 70 + 26
x = 96
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a) \(128-3\left(x+4\right)=23\)
\(\Rightarrow3\left(x+4\right)=128-23\)
\(\Rightarrow3\left(x+4\right)=105\)
\(\Rightarrow x+4=105:3\)
\(\Rightarrow x+4=35\)
\(\Rightarrow x=35-4\)
\(\Rightarrow x=31\)
Vậy x = 31
b) \(\left(6x-3^3\right).5^3=3.5^4\)
\(\Rightarrow6x-27=3.5^4:5^3\)
\(\Rightarrow6x-27=15\)
\(\Rightarrow6x=15+27\)
\(\Rightarrow6x=42\)
\(\Rightarrow x=42:6\)
\(\Rightarrow x=7\)
Vậy x = 7
c) \(2448:\left[119-\left(x-6\right)\right]=24\)
\(\Rightarrow119-\left(x-6\right)=2448:24=102\)
\(\Rightarrow x-6=119-102=17\)
\(\Rightarrow x=17+6=23\)
Vậy x = 23
d) \(130-\left[5.\left(9-x\right)+43\right]=47\)
\(\Rightarrow5.\left(9-x\right)+43=130-47=83\)
\(\Rightarrow5.\left(9-x\right)=83-43=40\)
\(\Rightarrow9-x=40:5=8\)
\(\Rightarrow x=9-8=1\)
Vậy x = 1
128 - 3( x+4 ) = 23
=> 3 (x+4) = 128 -23
=> 3(x+4) = 105
=> x+4 = 105 / 3
=> x+4 = 35
=> x = 35 - 4
=> x = 31
Vậy x = 31