Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
a) x - \(\frac{1}{9}\)= \(\frac{8}{3}\)
x = \(\frac{8}{3}\)+ \(\frac{1}{9}\)
x = \(\frac{24}{9}+\frac{1}{9}\)
x = \(\frac{25}{9}\)
tick cho mình nha! please!!!
Lời giải:
a.
$x=\frac{7}{25}+\frac{-1}{5}=\frac{7}{25}+\frac{-5}{25}=\frac{7-5}{25}=\frac{2}{25}$
b.
$x=\frac{5}{11}+\frac{4}{-9}=\frac{5}{11}-\frac{4}{9}=\frac{45}{99}-\frac{44}{99}=\frac{1}{99}$
c.
$\frac{x}{-1}=\frac{-1}{3}-\frac{5}{9}=\frac{-3}{9}-\frac{5}{9}=\frac{-8}{9}$
$x=(-1).\frac{-8}{9}=\frac{8}{9}$
Ta có : x + 1/4 = 9/x +1
x = 9/x +1 - 1/4
x = 36 - ( x + 1)/4x + 4
Làm theo ý hiểu về cái đề nhé. Khổ ghê viết không rõ ràng gì hết trơn (Mấy người toàn vậy!)
\(\frac{x+1}{4}=\frac{9}{x+1}\)
\(\Leftrightarrow\left(x+1\right)\left(x+1\right)=4.9\)
\(\Leftrightarrow\left(x+1\right)^2=36\)
\(\Leftrightarrow\left(x+1\right)^2=6^2\)
\(\Leftrightarrow x+1=6\)
\(\Leftrightarrow x=5\)
a) Ta có: \(x+\dfrac{1}{3}=\dfrac{2}{6}\)
\(\Leftrightarrow x+\dfrac{1}{3}=\dfrac{1}{3}\)
hay x=0
Vậy: x=0
b) Ta có: \(x-\dfrac{1}{4}=\dfrac{1}{-2}\)
\(\Leftrightarrow x-\dfrac{1}{4}=\dfrac{-1}{2}\)
\(\Leftrightarrow x=\dfrac{-1}{2}+\dfrac{1}{4}=\dfrac{-2}{4}+\dfrac{1}{4}=\dfrac{-1}{4}\)
Vậy: \(x=-\dfrac{1}{4}\)
c) Ta có: \(\dfrac{-1}{6}=\dfrac{3}{2}x\)
\(\Leftrightarrow x=\dfrac{-1}{6}:\dfrac{3}{2}=\dfrac{-1}{6}\cdot\dfrac{2}{3}\)
hay \(x=\dfrac{-1}{9}\)
Vậy: \(x=\dfrac{-1}{9}\)
a.
\(\dfrac{x}{9}=\dfrac{4}{x}\)
\(\Rightarrow x^2=4.9\)
\(\Rightarrow x^2=36\)
\(\Rightarrow\left[{}\begin{matrix}x=-6\\x=6\end{matrix}\right.\)
b.
\(\dfrac{x+1}{3}=\dfrac{3}{x+1}\)
\(\Rightarrow\left(x+1\right)^2=3^2\)
\(\Rightarrow\left[{}\begin{matrix}x+1=3\\x+1=-3\end{matrix}\right.\)
\(\Rightarrow\left[{}\begin{matrix}x=2\\x=-4\end{matrix}\right.\)
\(\dfrac{x}{9}=\dfrac{4}{x}\)
\(x^2=4.9\)
\(x^2=36\)
\(x^2=6^2\)
\(\Rightarrow\left\{{}\begin{matrix}x=6\\x=-6\end{matrix}\right.\)
\(---------\)
\(\dfrac{x+1}{3}=\dfrac{3}{x+1}\)
\(\left(x+1\right)^2=3.3=3^2\)
\(\Rightarrow\left(1\right):x+1=3\)
\(x=3-1\Rightarrow x=2.\)
\(\Rightarrow\left(2\right):x+1=-3\)
\(x=-3-1\Rightarrow x=-4\)
Từ \(\left(1\right)\) và \(\left(2\right)\), ta suy ra:
\(\Rightarrow x\in\left\{{}\begin{matrix}2\\-4\end{matrix}\right.\)