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Câu 10:
\(a,y\times7+y\times3=70\\ \Rightarrow y\times\left(7+3\right)=70\\ \Rightarrow y\times10=70\\ \Rightarrow y=7\\ b,18:y+12:y=3\\ \Rightarrow\left(18+12\right):y=3\\ \Rightarrow30:y=3\\ \Rightarrow y=10\)
câu 11:
\(a,9\times365+2\times365-365=\left(9+2-1\right)\times365=10\times365=3650\\ b,108:9-18:9=\left(108-18\right):9=90:9=10\\ c,43\times95+4\times43+43=43\times\left(95+4+1\right)=43\times100=4300\)
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\(a,\frac{x}{17}=\frac{60}{204}\Rightarrow x=\frac{60.17}{204}=5\)
\(b.6+\frac{x}{33}=\frac{7}{11}\)
\(\Leftrightarrow\frac{x}{33}=-\frac{59}{11}\)
\(\Rightarrow x=\frac{-59.33}{11}=-177\)
\(c,12+\frac{x}{43-x}=\frac{2}{3}\)
\(\Leftrightarrow\frac{x}{43-x}=-\frac{34}{3}\)
\(\Leftrightarrow3x=-1462+34x\)
\(\Leftrightarrow-31x=-1462\)
\(\Leftrightarrow x=\frac{1462}{31}\)
\(d,1< \frac{6}{x}< 2\)
\(\Leftrightarrow\frac{1}{6}< x< \frac{1}{3}\)
Mình vẫn chưa hiểu , bạn giải theo kiểu lớp 4 được không?
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543 x X - 43 x X = 2500
X x ( 543 - 43 ) = 2500
X x 500 = 2500
X = 2500 : 500
X = 5
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29/11 x X + 2/11 = 2/11
29/11 x X = 2/11 - 2/11
29/11 x X = 0
X = 0 : 29/11
X = 0
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\(1.x-\dfrac{2}{3}\times\left(x+9\right)=1\)
\(x-\dfrac{2}{3}\times x-6=1\)
\(x\times\left(1-\dfrac{2}{3}\right)=7\)
\(x\times\dfrac{1}{3}=7\)
\(x=21\)
\(2.x-\dfrac{11}{15}=\dfrac{3+x}{5}\)
\(\dfrac{15x}{15}-\dfrac{11}{15}=\dfrac{9+3x}{15}\)
\(15x-11=9+3x\)
\(12x=20\)
\(x=\dfrac{5}{3}\)
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x : 11 = 43 x2
x : 11 = 86
x = 11 x 86
x = 946
x= 946