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\(8.6+288:\left(x-3\right)^2=50\)
\(\Leftrightarrow48+288:\left(x-3\right)^2=50\Leftrightarrow288:\left(x-3\right)^2=2\)
\(\Leftrightarrow\left(x-3\right)^2=144\Leftrightarrow\left(x-3\right)^2=\left(\pm12\right)^2\)
TH1 : \(x-3=12\Leftrightarrow x=15\)
TH2 : \(x-3=-12\Leftrightarrow x=-9\)
Biến đổi được: (x-3)2=144=122=(-12)2
\(\Leftrightarrow\)\(\left[{}\begin{matrix}x-3=12\\x-3=-12\end{matrix}\right.\) \(\Leftrightarrow\left[{}\begin{matrix}x=15\\x=-9\end{matrix}\right.\)
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(8\cdot6+288:\left(x-3\right)^2=50\)
\(48+288:\left(x-3\right)^2=50\)
\(288:\left(x-3\right)^2=50-48=2\)
\(\left(x-3\right)^2=288:2=144\)
Vì x là số tự nhiên nên (x-3) là số tự nhiên.
\(\left(x-3\right)^2=12^2\)
\(x-3=12\)
\(x=12+3=15\)
![](https://rs.olm.vn/images/avt/0.png?1311)
= 48 + 288 : ( x - 3 )2 = 50
288 : ( x - 3 )2 = 50 - 48
288: ( x - 3 )2= 2
(x - 3 )2= 288 : 2
(x - 3)2= 144
(x - 3)2 = 122
x - 3 = 12
x = 12 + 3 = 15
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Bài 1:
a: Ta có: \(48751-\left(10425+y\right)=3828:12\)
\(\Leftrightarrow y+10425=48751-319=48432\)
hay y=38007
b: Ta có: \(\left(2367-y\right)-\left(2^{10}-7\right)=15^2-20\)
\(\Leftrightarrow2367-y=1222\)
hay y=1145
Bài 2:
Ta có: \(8\cdot6+288:\left(x-3\right)^2=50\)
\(\Leftrightarrow288:\left(x-3\right)^2=2\)
\(\Leftrightarrow\left(x-3\right)^2=144\)
\(\Leftrightarrow\left[{}\begin{matrix}x-3=12\\x-3=-12\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=15\\x=-9\end{matrix}\right.\)
![](https://rs.olm.vn/images/avt/0.png?1311)
5 . 2x+1 - 2x = 288
<=> 5 . 2x . 2 - 2x = 288
<=> 2x. (5.2 - 1 ) = 288
<=> 2x. 9 = 288
<=> 2x = 288 : 9
<=> 2x = 32
<=> 2x = 25
=> x = 5
Vậy x = 5
![](https://rs.olm.vn/images/avt/0.png?1311)
\(2^x+2^{x+3}=288\)
\(\Rightarrow2^x+2^x.2^3=288\)
\(\Rightarrow2^x\left(1+2^3\right)=288\)
\(\Rightarrow2^x.9=288\)
\(\Rightarrow2^x=288:9\)
\(\Rightarrow2^x=32\)
\(\Rightarrow2^x=2^5\)
\(\Rightarrow x=5\)
Vậy \(x=5\)
\(x+\left(x+1\right)+\left(x+2\right)+\left(x+3\right)+...+\left(x+30\right)=1240\)
\(\Rightarrow x+x+1+x+2+x+3+...+x+30=1240\)
\(\Rightarrow x+x+x+...+x+1+2+3+...+30=1240\)
Từ \(1\rightarrow30\)có: \(\left(30-1\right):1+1=30\)( số )
\(\Rightarrow31.x+\left(30+1\right).30:2=1240\)
\(\Rightarrow31.x+31.15=1240\)
\(\Rightarrow31.x+465=1240\)
\(\Rightarrow31.x=1240-465\)
\(\Rightarrow31.x=775\)
\(\Rightarrow x=775:31\)
\(\Rightarrow x=25\)
Chúc bạn học tốt !!!
x+(x+1)+(x+2)+....+(x+30)=1240
31 . x + (1 + 2 + 3 + 4 +...+ 29 + 30) = 1240
31 . x + 31.15 = 1240
31 . x = 1240 - 31.15
31 . x = 775
x = 775 : 31
x = 25
Vậy x=25
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
288:(x-3)2=2
=> (x-3)2=144
=>x-3=12(vì x thuộc N)
=> x=15
\(8.6+288:\left(x-3\right)^2=50\)
\(\Rightarrow48+288:\left(x-3\right)^2=50\)
\(\Rightarrow288:\left(x-3\right)^2=50-48=2\)
\(\Rightarrow\left(x-3\right)^2=288:2=144\)
Mà \(\left(x-3\right)^2=144=12^2\)
\(\Rightarrow x-3=12\)
\(\Rightarrow x=12+3\)
\(\Rightarrow x=15\)
=> 2x+2x.23=288
=>2x(1+23)=288
=>2x=32
=>2x=25
=>x=5
Tick nha
\(2^x+2^{x+3}=288\)
\(2^x\left(1+2^3\right)=288\)
\(2^x.9=288\)
\(2^x=32\)
\(2^x=2^5\)
\(\Rightarrow x=5\)