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212 + ( 48 - 2x ) : 40 - 3 = 3
212 +(48-2x):40 =3+3=6
=>212 + (48-2x) =6.40=240
=>(48-2x) =240-212 =28
48-2x=28
=>2x = 48-28 =20
=>x =20:2
=>x=10
\(212+\left(48-2.X\right):40-3=3\)\(=>212+\left(48-2.X\right):40=3+3\)
\(=>212+\left(48-2.X\right):40=6\)\(=>\left(48-2.X\right):40=6-212\)
\(=>\left(48-2.X\right):40=-206=>48-2.X=-206.40\)
\(=>48-2.X=-8240=>2.X=48--8240\)
\(=>2.X=8288=>X=8288:2\)
\(=>X=4144\)
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Bài làm
Sửa đề : \(\left(2x+3\right)-117=212\)( coppy lại đề nó vậy đấy, ko sao )
\(\Leftrightarrow2x+3=329\Leftrightarrow2x=326\Leftrightarrow x=163\)
(2x+ 3) - 117 = 212
=> 2x+ 3 = 212 + 171
2x+ 3 = 383
2x = 383 - 3
2x = 380
x = 380 : 2
x = 190
giúp mình nha
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[ 212 + ( 48 - 2 . x . x2 ) : 40 - 3 = 3
[ 212 + ( 48 - 2 . x . x2 ) : 40 = 3 + 3 = 6
[ 212 + ( 48 - 2 . x . x2 ) = 6 . 40 = 240
=> 48 - 2 . x . x2 = 240 - 212 = 28
2 . x . x2 = 48 - 28 = 20
x. x2 = 20 : 2 = 10
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a) \(2^x=8.64=2^3.2^6=2^9\Rightarrow x=9\)
b) \(3.2^x=48\Rightarrow2^x=16=2^4\Rightarrow x=4\)
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(2x2 + 1)(x-3)=0
\(\Rightarrow\orbr{\begin{cases}2x^2+1=0\\x-3=0\end{cases}}\)
\(\Rightarrow\orbr{\begin{cases}2x^2=-1\Rightarrow x^2=-\frac{1}{2}\left(vl\right)\\x=3\end{cases}}\)
Vậy x=3
48-(15-x)5=48
(15-x)5=48-48
(15-x)5=0
=> 15-x =0
x =15-0
x =15
Vậy x=15
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2x3 : 32 = 48
2x3 : 9 = 48
2x3 = 48.9
2x3 = 432
x3 = 432 : 2
x3 = 216
x3 = 63
=> x=6.
<=>(212+(48-2x)):40=6
<=>212+(48-2x)=240
<=>48-2x=28
<=>2x=20
<=>x=10
212+(48-2x):40=6
212+(48-2x)=240
48-2x=28
2x=20
x=10