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![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
a) Ta có:
\(24=2^3.3\)
\(10=2.5\)
\(ƯCLN\left(24;10\right)=2\)
\(BCNN\left(24;10\right)=2^3.3.5=120\)
__________
b) Ta có:
\(300=2^2.3.5^2\)
\(280=2^3.5.7\)
\(ƯCLN\left(300;280\right)=2^2.5=20\)
\(BCNN\left(300;280\right)=2^3.3.5^2.7=4200\)
__________
c) Ta có:
\(30=2.3.5\)
\(90=2.3^2.5\)
\(ƯCLN\left(30;90\right)=2.3.5=30\)
\(BCNN\left(30;90\right)=2.3^2.5=90\)
_________
d) Ta có:
\(14=2.7\)
\(21=3.7\)
\(56=2^3.7\)
\(ƯCLN\left(14;21;56\right)=7\)
\(BCNN\left(14;21;56\right)=2^3.3.7=168\)
\(#Wendy.Dang\)
![](https://rs.olm.vn/images/avt/0.png?1311)
Bài 1:
a: UCLN(30;90)=30
BCNN(30;90)=90
b: UCLN(140;210;56)=14
BCNN(140;210;56)=840
c: UCLN(105;84;30)=3
BCNN(105;84;30)=420
![](https://rs.olm.vn/images/avt/0.png?1311)
2.
a, x-13=-46
=>x=(-46)+13
=>x=33
b, 4x-6=22
=>4x=22+6
=>4x=28
=>x=28:4
=>x=7
3.
a, 32=25
48=24.3
=>ƯCLN(32,48)=24=16
16=24
72=23.32
=>ƯCLN(16,72)=23=8
b,
24=23.3
60=22.3.5
=>BCNN(24,60)=23.3.5=120
72=23.32
180=22.32.5
=>BCNN(72,180)=23.32.5=360
1) \(24=2^3.3\)
\(108=2^2.3^3\)
\(\Rightarrow\text{Ư}CLN_{\left(24;108\right)}=2^2.3=12\)
\(\Rightarrow BCNN_{\left(24;108\right)}=2^3.3^3=216\)
2) \(30=2.3.5\)
\(90=2.3^2.5\)
\(\Rightarrow\text{Ư}CLN_{\left(30;90\right)}=2.3.5=30\)
\(\Rightarrow BCNN_{\left(30;90\right)}=2.3^2.5=90\)
3)\(28=2^2.7\)
\(21=3.7\)
\(5=5\)
\(\Rightarrow\text{Ư}CLN_{\left(28;21;5\right)}=1\)
\(\Rightarrow BCNN_{\left(28;21;5\right)}=2^2.7.3.5=420\)
4) \(24=2^3.3\)
\(36=2^2.3^2\)
\(60=2^2.3.5\)
\(\Rightarrow\text{Ư}CLN_{\left(24;36;60\right)}=2^2.3=12\)
\(\Rightarrow BCNN_{\left(24;36;60\right)}=2^3.3^2.5=360\)
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