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a) 50 <2^n < 100
50 < 2^6
2^6 < 100
=> n = 6 duy nhất
b)50 < 7^n <2500
7^2 < 50 < 7^3
7^4 < 50^2 = 2500
n = 3 và 4
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\(a)P=\left\{343;2401\right\}\)
\(b)x-\left\{x-\left[x-\left(x+1\right)\right]\right\}=x-\left\{x-\left[x-x-1\right]\right\}\)
\(=x-\left\{x-x+x+1\right\}\)
\(=x-x+x-x-1=-1\)
a) \(n=\left\{3,4\right\}\)
b)\(x-\left\{x-\left[x-\left(x-1\right)\right]\right\}\)
\(=x-\left[x-\left(x-x+1\right)\right]\)
\(=x-\left(x-1\right)\)
\(=x-x-1=-1\)
_Tần vũ_
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a, Ta có:
\(50< 2^n< 100\)
\(\Rightarrow2^5+18< 2^n< 2^6+36\)
\(\Rightarrow5< n\le6\) (Vì \(2^6+36>2^6\))
\(\Rightarrow n=6\)
Vậy \(n=6\).
b, Ta có:
\(50< 7^n< 2500\)
\(\Rightarrow7^2+1< 7^n< 7^4+99\)
\(\Rightarrow2< n\le4\) (Vì \(7^4+99>7^4\))
\(\Rightarrow n\in\left\{3;4\right\}\)
Vậy \(n\in\left\{3;4\right\}\)
~ Chúc bạn học tốt ~!
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a) \(n=\left\{0;1;2;3\right\}\)
b) \(n=\left\{4;5;6\right\}\)
c) \(n=6\)
d) \(n=\left\{3;4;\right\}\)
a)n thuoc{1;2;3}
b)n thuoc{1;2;3;4;5;6}
c) n thuoc{1;2;4;5;6}
d)n thuoc{1;2;3;4;5;6}
a)n=6
b)n=3, n=4
a: 50<2^n<100
=>32<2^n<128
=>2^n=64
=>n=6
b: 50<7^n<2500
mà \(7^n\in\left\{7;49;343;2401;...\right\}\)
nên \(7^n\in\left\{343;2401\right\}\)
=>n=3 hoặc n=4