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a) S= 1+2+22+...+29
2S=2+22+23+...+210
2S-S=(2+22+23+...+210)-(1+2+23+...+29)
S=210-1
5.28=2.2+1.28=1+22.28=1+210
=>S=5.28
b) A=1+2+22+....+2100
2A=2+22+23+...+2101
2A-A=(2+22+23+...+2101)-(1+2+22+...+2100)
A=2101-1
=> A<2101
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2S=2(1+2+22+23+..+29)
2S=2+22+...+210
2S-S=(2+22+...+210)-(1+2+22+23+..+29)
S=210-1 (tới đây tách ra làm như Trinh Hai Nam)
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\(2S=2+2^2+2^3+2^4+...+2^{10}\)
=> \(2S-S=\left(2+2^2+2^3+2^4+...+2^{10}\right)-\left(1+2+2^2+2^3+...+2^9\right)\)
=> \(S=2^{10}-1=1024-1=1023\)
Mà \(5.2^8=5.256=1280\)
Vì 1023 < 1280
=> \(S<5.2^8\).
Ta có :
2S=2+2^2+2^3+...+2^10
2S-S=2+2^2+2^3+...+2^10-1-2-2^2-...-2^9
S=2^10-1
=>S<2^10 (1)
Ta lại có :
5.2^8>2^10 (2)
Tu (1) va (2) suy ra : S<5.2^8
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\(S=1+2+2^2+2^3+....+2^8+2^9.\)
\(\Rightarrow2S=\text{}2+2^2+2^3+....+2^8+2^9+2^{10}\)
\(\Rightarrow2S-S=\left(2+2^2+2^3+....+2^8+2^9+2^{10}\right)-\left(1+2+2^2+2^3+....+2^8+2^9\right)\)
\(S=2^{10}-1=1024-1=1023< 5\cdot2^8=5\cdot256=1280\)
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Cho S = 1+2+22+23+...+29
=> 2S = 2+22+23+...+29+210
=> 2S - S = S = 210 - 1 = 28 . 22 - 1 = 28 . 4 - 1
Ta có 5 . 28 = 4 . 28 + 28
Vì 1 < 28 nên S < 5 . 28
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a) Ta có: 2003^152>2003^20>199^20
Vậy 2003^152>199^20
b) Ta có: 3^39=(3^13)^3=1594323^3
11^21=(11^7)^3=19487171^3
Vì 1594323^3<19487171^3 nên 3^39<11^21
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S = 1 + 2 + 22 + 23 + ..... + 29
2S = 2 + 22 + 23 + .... + 29 + 210
2S - S = ( 2 + 22 + 23 + .... + 29 + 210 ) - ( 1 + 2 + 22 + 23 + ..... + 29 )
S = 210 - 1
Ta có :
5 . 28 = ( 4 + 1 ) . 28 = ( 22 + 1 ) . 28 = 22 . 28 + 1 . 28 = 210 + 28
=> 210 - 1 < 210 + 28
=> S < 210 + 28
ta có s=1+2+2^2+2^3+2^4+...+2^9
=>2s=2+2^2+2^3+2^4+...+2^10
=>s=(2^10-1)/2=2^9-1/2
đến đoạn này chắc bn so sánh đc rồi
\(2A=2+2^2+...+2^{10}\)
\(2A-A=\left(2+2^2+...+2^{10}\right)-\left(1+2+...+2^9\right)\)
\(A=2^{10}-1=1023\)
mà \(5\cdot2^8=1280\Rightarrow A< 5\cdot2^8\)
A = 1 + 2+22+23+...+29
2A = 2 + \(2^2+2^3+2^4+...+2^{10}\)
\(-\)
\(A=1+2+2^2+2^3+...+2^9\)
\(A=\)\(1-2^{10}\)
KL= tự so sánh nha