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Tìm x:
\(a.\dfrac{35}{28}-x=\dfrac{5}{14}\\ x=\dfrac{35}{28}-\dfrac{5}{14}\\ x=\dfrac{25}{28}\\ b.\dfrac{6}{7}\times x=\dfrac{2}{3}\\ x=\dfrac{2}{3}:\dfrac{6}{7}\\ x=\dfrac{7}{9}\\ c.x\times7=\dfrac{3}{4}\\ x=\dfrac{3}{4}:7\\ x=\dfrac{3}{28}\\ d.2:x-\dfrac{1}{3}=\dfrac{2}{5}\\ 2:x=\dfrac{2}{5}+\dfrac{1}{3}\\ 2:x=\dfrac{11}{15}\\ x=2:\dfrac{11}{15}\\ x=\dfrac{30}{11}.\)
\(a,\dfrac{35}{28}-x=\dfrac{5}{14}\)
\(x=\dfrac{35}{28}-\dfrac{5}{14}\)
\(x=\dfrac{25}{28}\)
\(b,\dfrac{6}{7}\times x=\dfrac{2}{3}\)
\(x=\dfrac{2}{3}:\dfrac{6}{7}\)
\(x=\dfrac{7}{9}\)
\(c,x\times7=\dfrac{3}{4}\)
\(x=\dfrac{3}{4}:7\)
\(x=\dfrac{3}{28}\)
\(d,2:x-\dfrac{1}{3}=\dfrac{2}{5}\)
\(2:x=\dfrac{2}{5}+\dfrac{1}{3}\)
\(2:x=\dfrac{11}{15}\)
\(x=2:\dfrac{11}{15}\)
\(x=\dfrac{30}{11}\)
#YVA
\(a)\frac{5}{12}+\frac{3}{14}+\frac{7}{12}=\left(\frac{5}{12}+\frac{7}{12}\right)+\frac{3}{4}=1+\frac{3}{4}=\frac{7}{4}\)
\(b)\frac{15}{14}\times\frac{17}{18}\times\frac{28}{15}=\frac{15\times17\times28}{14\times18\times15}=\frac{17}{9}\)
\(c)\frac{5}{8}\times\frac{5}{4}+\frac{5}{4}\times\frac{3}{8}=\frac{5}{4}\times\left(\frac{5}{8}+\frac{3}{8}\right)=\frac{5}{4}\times1=\frac{5}{8}\)
\(a)\frac{5}{12}+\frac{3}{14}+\frac{7}{12}=\left(\frac{5}{12}+\frac{7}{12}\right)+\frac{3}{4}=1+\frac{3}{4}=\frac{7}{4}\)
\(b)\frac{15}{14}\times\frac{17}{18}\times\frac{28}{15}=\frac{15\times17\times28}{14\times18\times15}=\frac{17}{9}\)
\(c)\frac{5}{8}\times\frac{5}{4}+\frac{5}{4}\times\frac{3}{8}=\frac{5}{4}\times\left(\frac{5}{8}+\frac{3}{8}\right)=\frac{5}{4}\times1=\frac{5}{8}\)
~Học tốt~
b, 3/5 + 4/7 + 2/8 + 10/25 + 9/21 + 28/16
= 3/5 + 4/7 + 2/8 + 2/5 + 3/7 + 14/8
= (3/5 + 2/5) + ( 4/7 + 3/7) + ( 2/8 + 14/8)
= 1 + 1 + 7/4
= 2 + 7/4 = 15/4
c , 8/7 + 7/6 + 5/8 + 10/12 + 24/28 + 6/16
= c , 8/7 + 7/6 + 5/8 + 5/6 + 6/7 + 1/2
= (8/7 + 6/7) + (7/6 + 5/6) + 5/8 + 1/2
= 14/7 + 12/6 + 5/8 + 1/2
= 2 + 2 + 5/8 + 1/2
= 4 + 9/8 = 41/8
| a | b | c | a x (b + c) | a x b + a x c |
|---|---|---|---|---|
| 4 | 5 | 2 | 4 x (5 + 2) = 28 | 4 x 5 + 4 x 2 = 28 |
| 3 | 4 | 5 | 3 x (4 + 5) = 27 | 3 x 4 + 3 x 5 = 27 |
| 6 | 2 | 3 | 6 x (2 + 3) = 30 | 6 x 2 + 6 x 3 = 30 |
| a | b | c | a x ( b + c ) | a x b + a x c |
| 4 | 5 | 2 | 4 x ( 5 + 2 ) = 28 | 4 x 5 + 4 x 2 = 28 |
| 3 | 4 | 5 | 3 x ( 4 + 5 ) = 27 | 3 x 4 + 3 x 5 = 27 |
| 6 | 2 | 3 | 6 x ( 2 + 3 ) = 30 | 6 x 2 + 6 x 3 = 30 |
| a | b | c | a x (b + c) | a x b + a x c |
|---|---|---|---|---|
| 4 | 5 | 2 | 4 x (5 + 2) = 28 | 4 x 5 + 4 x 2 = 28 |
| 3 | 4 | 5 | 3 x (4 + 5) = 27 | 3 x 4 + 3 x 5 = 27 |
| 6 | 2 | 3 | 6 x (2 + 3) = 30 | 6 x 2 + 6 x 3 = 30 |
a) \(\dfrac{4}{7}+\dfrac{2}{8}=\dfrac{32}{56}+\dfrac{14}{56}=\dfrac{46}{56}=\dfrac{23}{28}\)
b) \(\dfrac{8}{6}-\dfrac{8}{24}=\dfrac{32}{24}-\dfrac{8}{24}=\dfrac{24}{24}=1\)
c) \(\dfrac{9}{28}\times\dfrac{14}{9}=\dfrac{126}{252}=\dfrac{1}{2}\)
d) \(\dfrac{7}{6}\div\dfrac{2}{3}=\dfrac{7}{6}\times\dfrac{3}{2}=\dfrac{21}{12}\)
1. \(\dfrac{4}{7}+\dfrac{2}{8}=\dfrac{32}{56}+\dfrac{14}{56}=\dfrac{32+14}{56}=\dfrac{46}{56}=\dfrac{23}{28}\)
2. \(\dfrac{8}{6}-\dfrac{8}{24}=\dfrac{32}{24}-\dfrac{8}{24}=\dfrac{32-8}{24}=\dfrac{24}{24}=1\)
3. \(\dfrac{9}{28}\text{×}\dfrac{14}{9}=\dfrac{9\text{×}14}{28\text{×}9}=\dfrac{126}{252}=\dfrac{7}{14}\)
4. \(\dfrac{7}{6}:\dfrac{2}{3}=\dfrac{7}{6}\text{×}\dfrac{3}{2}=\dfrac{7\text{×}3}{6\text{×}2}=\dfrac{21}{12}=\dfrac{7}{4}\)
12/36 = 12 :12 / 36 : 12 = 1/3
14/28 = 14 : 14 / 28 : 14 = 1/2
a,
8/12-1/4= 8/12-3/12 = 5/12
b,
4/7*5/2:5/14 = 10/7:5/14=4
c,
x:1/47=16=>x=16*1/47= 16/47
d,
mẹ: 32 tuổi
con:4 tuổi
NHỚ ****!!!!
\(a.\frac{8}{12}-\frac{1}{4}\)
\(=\frac{8}{12}-\frac{3}{12}\)
\(=\frac{5}{12}.\)
\(b.\frac{4}{7}x\frac{5}{2}:\frac{5}{14}\)
\(=\frac{10}{7}:\frac{5}{14}\)
\(=\frac{10}{7}x\frac{14}{5}\)
\(=4.\)
\(c.x:\frac{1}{4}=16\)
\(x=16x\frac{1}{4}\)
\(x=4.\)
d. Giải
Sau 3 năm nữa mẹ vẫn hơn con 28 tuổi. Vì khi đó mẹ gấp 5 lần tuổi con nên hiệu số phần bằng nhau là:
5-1= 4 (phần)
Khi đó tuổi con là:
28:4=7 (tuổi)
Tuổi của con là:
7-3=4 (tuổi)
Tuổi của mẹ là:
4+28=32 (tuổi)
Đáp số: 4 tuổi.
32 tuổi.
bạn có chắc chắn đây là toán lớp 4 không???
đây đâu phải toán lớp 4